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tennisfan
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hi guys,
I came across this pratice test online and needed some clarifications. the question is What is the range of host addresses that resides on the same network as 135.10.17.67 255.255.240.0?
a) 135.10.0.1 to 135.10.0.254
b) 135.10.0.0 to 135.10.0.255
c) 135.10.16.1 to 135.10.31.254
d) 135.10.16.0 to 135.10.32.0
e) None of the above
answer is c, and understand how to get this. I learned the 256 - subnet mask trick, but the question did not specify valid host and if it did then the answer would be "e", since 135.10.31.254 is the broadcast address....am I right?
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 01-08-01 09:19 AM
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dmaftei
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quote:
Originally posted by tennisfan:
I learned the 256 - subnet mask trick, but the question did not specify valid host and if it did then the answer would be "e", since 135.10.31.254 is the broadcast address....am I right?
Sorry, you're not right. Here's your subnets:
- 135.10.0.0
- 135.10.16.0
- 135.10.32.0
- etc
135.10.17.67 falls in 135.10.16.0. Broadcast is "next subnet minus 1", that is "135.10.32.0 - 1", that is 135.10.31.255. The last host is "broadcast minus 1", that is 135.10.31.254. So c) is correct.
Cheers!
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01-08-01 09:38 AM
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lennon57
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I'll agree with you dmaftei. The way I understand it, 135.10.32.0 would start the third subnet, and 135.10.31.255 would be the broadcast address.
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01-08-01 10:58 AM
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tennisfan
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thanks guys I didn't mean to ask such basic question but the part that confused me is would the exam ask questions in this way, because I would think the fact that answer "e" was there, makes it a little ambiguous. since subnet address and broadcast address are not really valid hosts and therefore not usable.
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01-08-01 07:59 PM
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tennisfan
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01-08-01 08:01 PM
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