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Pages (2): [1] 2 »
adilux
Senior Member
M
Registered: Nov 2000
Location: Kansas City, Ohio
Country: United States
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Certifications: CCNA
Working on: Some sort of Internet Security Cert.
Total Posts: 201
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 11-28-00 10:25 AM
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rore2246
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Treat it as a class C address for purposes of subnetting.
256-192=64
Subnet addresses: 64, 128, 192
The subnet is: 128
Broadcast address: 191
Host range: 172.16.2.129-172.16.2.190
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B.S. in Telecommunications Management, Network+, CCNA - Still can't type, still no job!
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11-28-00 10:38 AM
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freak
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Registered: Aug 2000
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Country: USA
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Certifications: MA, M.Ed., Net+,I-Net+, Security+, CEH, CEI, CCA, CCNA, MCP+I, MCSA, MCSE NT 4.0, MCSE 2000, MCT
Working on: MCSE 2K3, Linux+, CISSP
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11-29-00 06:21 AM
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firechicken
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Working on: Food Handler
Total Posts: 467
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11-29-00 11:49 PM
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aktribes
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Registered: Aug 2000
Location: Anch, AK, USA
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11-30-00 12:29 AM
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Mix
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256-192=64
Subnet addresses: 64, 128
This part is right. But you didn't break down the subnets and broadcasts.
64 Network Address
65 First user(host address)
126 Last user(host address)
127 Broadcast address
This is Class C
[This message has been edited by Mix (edited 11-29-2000).]
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11-30-00 01:18 AM
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Mix
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Cont. from above post.
128 Network address
129 First user(host address)
190 Last user(host address)
191 Broadcast address
This is the proper way of breaking down a Class C structure.
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11-30-00 01:27 AM
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OKLANman
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Registered: Nov 2000
Location: OKC, OK USA
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Working on: MCP 2k
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Mix, I'm confused. I don't see where rore is wrong. Broadcast=191 first subnet=128 first host=129 last host=190. Same thing you came up with I thought.
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11-30-00 01:42 AM
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OKLANman
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Location: OKC, OK USA
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quote:
Originally posted by OKLANman:
Mix, I'm confused. I don't see where rore is wrong. Broadcast=191 first subnet=128 first host=129 last host=190. Same thing you came up with I thought.
Sorry bout that 3rd subnet=128
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11-30-00 01:44 AM
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freak
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Working on: MCSE 2K3, Linux+, CISSP
Total Posts: 9688
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11-30-00 07:17 AM
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