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CompTIA > A+ forum > OS Question on Wrap-around. HELLLP!!!

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Author OS Question on Wrap-around. HELLLP!!!
Mauwakee
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Question OS Question on Wrap-around. HELLLP!!!

Hi. In Michael Myers 3rd edition, chapter 12, DOS Memory in a Windows World, page 836; he talks about wrap-around. I have read this several times and it stills seems fuzzy to me. Not a good fuzzy either. Can anyone explain it better for me?
Thanks

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Mauwakee
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SomeGuy
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Wrap-around is when you try to address memory that a CPU cannot reach with its address bus. The 8088 can't "see" higher than FFFFF because it doesn't have enough wires to represent a 6th digit. So 10FFFF would be interpreted as 0FFFF. This makes the bus "wrap around" to a lower place on the address bus.

It's the same as Y2K. Non-Y2K compliant computers can't go higher than 1999 because they only use two digits. 1999 is 99, so 2000 is seen as 00 which is assumed to be 1900 by the system. It too is doing a kind of "wrap-around".

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cm2gj
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quote:
Originally posted by SomeGuy
Wrap-around is when you try to address memory that a CPU cannot reach with its address bus. The 8088 can't "see" higher than FFFFF because it doesn't have enough wires to represent a 6th digit. So 10FFFF would be interpreted as 0FFFF. This makes the bus "wrap around" to a lower place on the address bus.

It's the same as Y2K. Non-Y2K compliant computers can't go higher than 1999 because they only use two digits. 1999 is 99, so 2000 is seen as 00 which is assumed to be 1900 by the system. It too is doing a kind of "wrap-around".



nice.

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Mauwakee
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Talking

Thanks that helped.

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Mauwakee
It my name in Shawnee.
That is a American Indian Nation.

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Old Post 11-21-02 10:52 PM
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