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naeem
Member

Registered: Aug 2001 Location: Islamabad Country: Pakistan State: Certifications: MCSD Working on: MCDBA
Total Posts: 53
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Raid 5
While implementing RAID 5 , u need 3 hard disk at least. at each hard disk along with data some parity informations r written too.in case of any one of the hard disk failure , other 2 hard disk r able to recover its data.
now my question is
---- what kind of parity informations is?
I mean what is its structure ?
Is it some kind of backup. if this is backup then it means there will huge amount of redundatnt data (excessive amont of data repetition)
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Naeem!
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11-22-01 05:38 AM
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Vidra
Junior Member M
Registered: May 2001 Location: Rustenburg Country: South Africa State: Certifications: MCSE NT 4.0,MCSE 2000, A+, Net+, MCP+I, MCP, SQL 2000(Admin) Working on: MCDBA, MCSD, Server+, I-Net+, MOUS
Total Posts: 27
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Parity
Here Is A Parity Table (Sort OF)
(Parity)
0 + 0 = 1
0 + 1 = 0
1 + 0 = 0
1 + 1 = 1
hope this helps!?
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Courage is not the absence of fear, but the presence of it.
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11-22-01 08:51 AM
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colinbun
Junior Member
Registered: Nov 2001 Location: Country: United Kingdom State: Certifications: MCDBA Working on:
Total Posts: 2
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Re: Raid 5
You are absolutely right about the amount of disk used in raid 5. For example, if you have only 3 disks, data is written to disks 1 & 2 to start with, with parity written to disk3. For the next read, disk 1 might have the parity data, then disk 2 and so on. As you can see, you have just lost a third of your disk size.
The whole formula is
lost space = 1 / number of disks
ie. a third for 3, a quarter for 4 and so on.
Cheers,
Colin
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11-22-01 01:33 PM
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