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Microsoft (MCSE, MCSD, MOUS, MCAD) > 70-216 > Subnetting Question

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Author Subnetting Question
ldbeane
Junior Member




Registered: Jun 2002
Location:
Country: United States
State:
Certifications: MCP
Working on: MCSA; MCSE; MCDBA

Total Posts: 1
Subnetting Question

I have the mspress book for 70-216. In the subnetting chapter it has a question stated:
You are the new administrator of a 2000 node network. There is only one router on the entire network, which provides all the computers with Internet access. The company's ISP has assigned the following eight network addresses to them:
10.24.32.0/24
10.24.33.0/24
10.24.34.0/24
10.30.35.0/24
10.30.36.0/24
10.30.37.0/24
10.30.38.0/24
10.30.39.0/24

What subnet mask could you use to minimize the complexity of the routing tables while maintaining the existing Internet connectivity?
a.) 255.255.252.0
b.) 255.255.255.252
c.) 255.255.255.248
d.) 255.255.248.0

The book says the answer is d.

Could someone please explain this. I don't see how this is possible with the second byte in the address being 24 and 30.

Thanks.

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Old Post 08-10-05 07:51 PM
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enforcer
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Registered: Jun 2002
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Working on: MCSE 2K 216,217 MCSA 2K 218

Total Posts: 10898

My guess that there is a misprint and that all the second numbers should be a '30'. check the mspress website and see if there have been any corections that cover this question.

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Old Post 09-05-06 05:14 PM
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luisjo
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Registered: Jun 2002
Location: Guatemala
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Certifications: MCP,Net+,I-Net+,CIWA, MCSA,CIK,CTS,NTS,CF95/98,MSW95N,MF,BM
Working on: MCDBA, MCSE,CWNA,CCDA, CCNA, SECURITY+,SERVER+, A+,CIWD,CIWS, CIWP, & EVERY CERT THAT PAYS GOOD

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Cool these is why they print these answer

There most be 1,900 users on these subnet, at least 11 digits must be use for these 1,900 clients. since 2**11 is =2,048 and 2**10 = 1,024 these leaves 21 (32-11) bits for the subnet mask.

Subnet mask in binary 11111111,11111111,11111000,000
00000

subnet mask in decima
255.255.248.0

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Old Post 01-29-07 06:04 AM
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namrak
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Registered: Aug 2002
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Working on: BS/IT, 70-216, 70-217, CCNA

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Thats perfect luisjo. This is exactly how to solve the problem because of finding the subnet that will allow for the requested amount of users of 1900. This automatically rules out answers B and C so now you need to determine between A and D which luisjo has so aptly illustrated.

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Old Post 02-13-07 09:12 PM
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