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Microsoft (MCSE, MCSD, MOUS, MCAD) > 70-218 > 70-218 Q of the Day Wednesday 8/13

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Author 70-218 Q of the Day Wednesday 8/13
mrfixit
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Registered: Jul 2001
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70-218 Q of the Day Wednesday 8/13

Here we go again!


Deja-Vue is the network administrator for Long Beach Networks. His network consists of 100 computers running Windows 95, 125 computers running Windows 98, and 240 computers running Windows 2000 Professional. All computers are located on the same network segment. Lynne, his supervisor, has asked Deja to automate the process of assigning IP addresses (the addresses range is from 130.67.5.1 to 130.67.6.254). What does Deja-Vue need to configure?


A)Install DHCP and configure DNS integration.
B)Install DHCP and configure a scope.
C)Install DHCP and configure a superscope.
D)Install DHCP and configure BOOTP.


See you tomorrow with the answer!

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Old Post 08-13-03 02:50 PM
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jeff50ho
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Working on: MCSA(just one more test 70-218)

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Post B

Since we only have 1 network segment i'll say B.

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Old Post 08-13-03 03:07 PM
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karlisi
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C
actually there are two scopes with network ID's 130.67.5.0 and 130.67.6.0 which Deja-Vue should join in one superscope

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Old Post 08-13-03 03:08 PM
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isles1
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C

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Old Post 08-13-03 04:32 PM
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mrfixit
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Re: 70-218 Q of the Day Wednesday 8/13

Well, I have to say I'm a little disappointed in the response to this question. It wasn't that hard, was it?

Here is the answer:


quote:
Originally posted by mrfixit

Deja-Vue is the network administrator for Long Beach Networks. His network consists of 100 computers running Windows 95, 125 computers running Windows 98, and 240 computers running Windows 2000 Professional. All computers are located on the same network segment. Lynne, his supervisor, has asked Deja to automate the process of assigning IP addresses (the addresses range is from 130.67.5.1 to 130.67.6.254). What does Deja-Vue need to configure?


C)Install DHCP and configure a superscope.





B could be a good answer but because you have 465 computers on the same segment, you will need to get two Class C addresses and configure a superscope.

Well done to those of you that did respond.

__________________
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Give a man a fish and you feed him for a day, teach him to use the Net and he won't bother you for weeks.

What goes up must come down. Ask any system administrator.

If a trainstation is where the train stops, what's a workstation...?

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Old Post 08-14-03 03:10 PM
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Spid
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Cool Re: 70-218 Q of the Day Wednesday 8/13

quote:
Originally posted by mrfixit
B could be a good answer but because you have 465 computers on the same segment, you will need to get two Class C addresses and configure a superscope.


Sorry, I disagree. You didn't specify a subnet mask, so how do you know that 130.67.5.0 and 130.67.6.0 are not on the same network/subnetwork? Also, 465 hosts shouldn't pose a problem on this single segment.

So, that's a Class B address scope on a single segment. No mask specified, have to assume default classful mask (255.255.0.0).

You should have no problem allocating Class B addresses to 465 clients located on a single segment via DHCP with a single scope.

Network Address : 130.67.0.0
Subnet Mask : 255.255.0.0
Number of Subnets : 1
Hosts per Subnet : 65534

Entire Range : 130.67.0.1 to 130.67.255.254

Setup the Scope to be 130.67.5.1 - 130.67.6.254

"B" would do the trick.

I'd agree with "C" if you specified a Class "C" subnet mask (255.255.255.0).

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Last edited by Spid on 08-14-03 at 07:44 PM

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Old Post 08-14-03 07:35 PM
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mrfixit
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Re: Re: 70-218 Q of the Day Wednesday 8/13

quote:
Originally posted by Spid
Sorry, I disagree. You didn't specify a subnet mask, so how do you know that 130.67.5.0 and 130.67.6.0 are not on the same network/subnetwork? Also, 465 hosts shouldn't pose a problem on this single segment.

So, that's a Class B address scope on a single segment. No mask specified, have to assume default classful mask (255.255.0.0).

You should have no problem allocating Class B addresses to 465 clients located on a single segment via DHCP with a single scope.

Network Address : 130.67.0.0
Subnet Mask : 255.255.0.0
Number of Subnets : 1
Hosts per Subnet : 65534

Entire Range : 130.67.0.1 to 130.67.255.254

Setup the Scope to be 130.67.5.1 - 130.67.6.254

"B" would do the trick.

I'd agree with "C" if you specified a Class "C" subnet mask (255.255.255.0).



Okay, the subnet is 255.255.255.0. (Next time I'll be sure to include it.) I must have a faulty calculator though, and the addresses being used are 130.67.5.1 to 130.67.6.254,(granted the range is 130.67.0.0 to 130.67.255.255), that gives you 254 host. If you Supernet using a mask of 255.255.0.0, then you would get 65534 host. Right?

__________________
Keyboard not functioning. Press F1 to continue....

Give a man a fish and you feed him for a day, teach him to use the Net and he won't bother you for weeks.

What goes up must come down. Ask any system administrator.

If a trainstation is where the train stops, what's a workstation...?

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Old Post 08-14-03 09:30 PM
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