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Home > Archive > alt.certification.mcse > February 2003 > Transcender 218
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| borsky 2003-02-14, 4:24 am |
| Hi
Here are some of the answers/explanation I read in Transcender and think
they are not correct. What do you think?
1. "...DNS servers cannot resolve single-part names to IP addresses"
(single-part: I have never seen this expression before it might refer to
single label, unqualified names.)
2."...You should not create the same Active-Directory integrated zone on
domain controllers for different domains because those zones would not be
automatically syncronized"
(Two domains: A and B. Dns zones are active-dir-integrated in both domains.
Dns in A can resolve names in both domains, but Dns in B can only resolve
names in B. You want users in B to be able to resolve names in both domains.
Transcender's answer:In B inplement a secondary zone for A)
Source: Trancender 70-218 question A52 and B23
I also found two incorrect answers about subnetting one of wich has been
corrected. The other one is this:
Question A24: you plan to set up 4 subnets with up to 20 host on each.
You'll use 192.168.0.0/24 private addr. Which subnet mask should you assign?
a. 255.255.255.192
b. 255.255.255.224
What is your suggestion?
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| Gekkenhuis X 2003-02-15, 11:24 am |
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> I also found two incorrect answers about subnetting one of wich has been
> corrected. The other one is this:
> Question A24: you plan to set up 4 subnets with up to 20 host on each.
> You'll use 192.168.0.0/24 private addr. Which subnet mask should you
assign?
> a. 255.255.255.192
> b. 255.255.255.224
>
> What is your suggestion?
>
I am not that good in subnetting but I would say 255.255.255.0.
Gr.
Chris
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| Gekkenhuis X 2003-02-15, 11:24 am |
| Ok, nevermind that! I just re-read my own answer. Told you I wasn't that
good (I actually suck!) :-)
Gr.
Chris
"Gekkenhuis X" <cdebruin01REMOVETHIS@hotmail.com> schreef in bericht
news:b2lqo9$1dnfu1$1@ID-166883.news.dfncis.de...
>
> > I also found two incorrect answers about subnetting one of wich has been
> > corrected. The other one is this:
> > Question A24: you plan to set up 4 subnets with up to 20 host on each.
> > You'll use 192.168.0.0/24 private addr. Which subnet mask should you
> assign?
> > a. 255.255.255.192
> > b. 255.255.255.224
> >
> > What is your suggestion?
> >
> I am not that good in subnetting but I would say 255.255.255.0.
>
> Gr.
> Chris
>
>
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"Gekkenhuis X" <cdebruin01REMOVETHIS@hotmail.com> wrote in message
news:b2lqo9$1dnfu1$1@ID-166883.news.dfncis.de...
>
> > I also found two incorrect answers about subnetting one of wich has been
> > corrected. The other one is this:
> > Question A24: you plan to set up 4 subnets with up to 20 host on each.
> > You'll use 192.168.0.0/24 private addr. Which subnet mask should you
> assign?
> > a. 255.255.255.192
> > b. 255.255.255.224
> >
> > What is your suggestion?
Because it's a class C address we know the first three octects of the IP
address are for the network ID, and the 4th is for the host ID. We can
split the fourth one up and use it for subnets if we need to. So start by
converting it into binary:
128 64 32 16 8 4 2 1
We are told that we need 4 subnets. So, we need to work out the minimum
amount of bits that would give us 4 unique addresses. Using the 1st bit
would give us 2 - 0 or 1. Using the 1st and 2nd bit would give us 4 (2x2)
BUT we cannot have and address of all 0's or all 1's because they are used
for broadcasts. So that gives us (2x2)-2 ie number of bits x number of
values - 2. Using the 1st, 2nd and 3rd bit would give us the required
number of subnets: 3 x 2 - 2 = 4.
So now we know that we have to use the first three bits of the host ID octet
to use for subnets.
Subnet Host ID
(128 64 32) (16 8 4 2 1)
Adding the numerical values of these bits together gives us 224. So the
subnet mask will be 255.255.255.224.
Bear in mind that now we have stolen 3 of the Host ID bits for subnets, we
only have the final 5 bits of the octet to use for host ID's. 16 + 8 + 4 +
2 + 1 = 31. So we could only every have 31 hosts on this network. That's
OK in this scenario but in the real world we would probably need to use a
class B address for the additional 8 bits to use for host addresses. So
work out how to calculate class B addresses. You will more than likely find
them on the exam.
Col.
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