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Home > Archive > alt.certification.network-plus > January 2004 > I Passed!
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| Aaron Appelbaum 2003-11-07, 5:24 am |
| Hello all. I passed with a score of 793. I had a question I hope one
of you can answer.
The network is 198.168.10.0/24. You wish to add a node to the network.
What would be a valid address?
a. 192.168.1.10
b. 192.168.10.10
c. 192.168.10.254
d. 192.168.10.255
I picked B. I've never seen the foward slash with a number after a
network address before. Does that refer to subnetting? What does it
mean?
Aaron Appelbuam
A+, Network+
| |
| C Voyer 2003-11-07, 2:24 pm |
|
"Aaron Appelbaum" <aaronappelbaum.remove.@yahoo.com> wrote in message
news:qjcgqvc8fnclb66u86m2ifjgj
0r929ju8s@4ax.com...
> Hello all. I passed with a score of 793. I had a question I hope one
> of you can answer.
>
> The network is 198.168.10.0/24. You wish to add a node to the network.
> What would be a valid address?
>
> a. 192.168.1.10
> b. 192.168.10.10
> c. 192.168.10.254
> d. 192.168.10.255
>
>
> I picked B. I've never seen the foward slash with a number after a
> network address before. Does that refer to subnetting? What does it
> mean?
>
> Aaron Appelbuam
> A+, Network+
The / followed by the number tells you that the network part of the address
is 24 bits long....therfore, it would be the first 3 octets
192.168.10
The last octet would be the host number
| |
|
| I will try to keep this short.
192.168.10.10 and 192.168.10.254 would be valid.
192.168.10.0/24 means this is a class C address using the first 24 bits (3
octets) for the Network ID and the last 8 bits for Host ID with a subnetmask
/24 which also is the same as 255.255.255.0. In other words /## is just
another way to express a SubNetMask.
Subnetting is when you divide a Network ID into multiple logical subnets and
the Network ID consists of Classful Network ID plus bits borrowed from Host
ID.
/8 /16 /24 is not Subnetting but Classfull Network IDs.
Congratulations to passing without knowing anything about networking.
AT
"Aaron Appelbaum" <aaronappelbaum.remove.@yahoo.com> wrote in message
news:qjcgqvc8fnclb66u86m2ifjgj
0r929ju8s@4ax.com...
> Hello all. I passed with a score of 793. I had a question I hope one
> of you can answer.
>
> The network is 198.168.10.0/24. You wish to add a node to the network.
> What would be a valid address?
>
> a. 192.168.1.10
> b. 192.168.10.10
> c. 192.168.10.254
> d. 192.168.10.255
>
>
> I picked B. I've never seen the foward slash with a number after a
> network address before. Does that refer to subnetting? What does it
> mean?
>
> Aaron Appelbuam
> A+, Network+
| |
| Aaron Appelbaum 2003-11-08, 3:26 am |
| Thanks A LOT for the encouragement.
>Congratulations to passing without knowing anything about networking.
>
>AT
>
| |
|
|
| Dave Watson 2003-11-08, 5:24 am |
|
"Aaron Appelbaum" <aaronappelbaum.remove.@yahoo.com> wrote in message
news:qjcgqvc8fnclb66u86m2ifjgj
0r929ju8s@4ax.com...
>
> The network is 198.168.10.0/24. You wish to add a node to the network.
> What would be a valid address?
>
> a. 192.168.1.10
> b. 192.168.10.10
> c. 192.168.10.254
> d. 192.168.10.255
The correct answers are b and d
192.168.10.0 - .255 - the first three octets are network addresses in the
example specified so the first 24 bits are reserved - hence /24.
Dave.
Glad you passed - all the best.
Dave.
| |
| Charles M. Kozierok 2003-11-08, 8:24 am |
| In article <GyTqb.1666$nz.643@newsread2.news.pas.earthlink.net>,
AT <torgny@@direcway.com> wrote:
} 192.168.10.0/24 means this is a class C address using the first 24 bits (3
} octets) for the Network ID and the last 8 bits for Host ID with a subnetmask
} /24 which also is the same as 255.255.255.0. In other words /## is just
} another way to express a SubNetMask.
} Subnetting is when you divide a Network ID into multiple logical subnets and
} the Network ID consists of Classful Network ID plus bits borrowed from Host
} ID.
} /8 /16 /24 is not Subnetting but Classfull Network IDs.
Most of this is true but not all is technically correct. 
The "slash notation" is what is used in *classless* addressing, not
classful. Also known as Classless Inter-Domain Routing (CIDR).
It is true that slash notation and subnet mask notation are often
interchanged but CIDR is not the same as subnetting and is not based on
network classes at all and does not use subnet masks in the way that
classful subnetting used that concept.
peace,
-*-
charles
| |
| David K 2003-11-08, 11:25 am |
| On Fri, 07 Nov 2003 01:36:22 -0800, Aaron Appelbaum
<aaronappelbaum.remove.@yahoo.com> wrote:
>Hello all. I passed with a score of 793. I had a question I hope one
>of you can answer.
>
>The network is 198.168.10.0/24. You wish to add a node to the network.
>What would be a valid address?
>
>a. 192.168.1.10
>b. 192.168.10.10
>c. 192.168.10.254
>d. 192.168.10.255
B, IIRC, was actually 192.167.10.10. C was the only correct answer
here. A is in the wrong network, and D is a broadcast address.
Dave
| |
|
| Hi Aaron-- congratlations on passing! Coincidentally, I passed this
morning with a 793, too!
On your 198.168.10.0/24 question, I remember that one, but I think you
got one of the choices wrong. Choice B was "192.167.10.10". I know,
because I was just about to pick B until I noticed the "7", which
would put it outside the range of private addresses. I chose "C"
instead. I really had to look closely to spot the difference.
The /24 is the number of bits allowed for the host ID. This is one
that I struggled with for a long time until I happened across it in my
Mike Meyers Net+ book. It is referred to as CIDR (classless
inter-domain routing) notation. I first saw it in my college
networking class, but missed the explanation for it, so I was glad
when I happened to find it before the test!
I think that if the CIDR question was enough to prove that you know
nothing about networking then CompTIA could have made a much shorter
(i.e. one question) test.
IMO, this was the second hardest certification test I've taken yet,
with the most difficult being NCR's Teradata and the easiest being A+.
I'll be taking MSSQL Server 2003 next.
Thanks to all the posters here for the insight on the test-- it was
invaluable to me today and will certainly serve me well in my career.
John Davis
Network+, A+, TCP
Aaron Appelbaum <aaronappelbaum.remove.@yahoo.com> wrote in message news:< qjcgqvc8fnclb66u86m2ifjgj0r929
ju8s@4ax.com>...
> Hello all. I passed with a score of 793. I had a question I hope one
> of you can answer.
>
> The network is 198.168.10.0/24. You wish to add a node to the network.
> What would be a valid address?
>
> a. 192.168.1.10
> b. 192.168.10.10
> c. 192.168.10.254
> d. 192.168.10.255
>
>
> I picked B. I've never seen the foward slash with a number after a
> network address before. Does that refer to subnetting? What does it
> mean?
>
> Aaron Appelbuam
> A+, Network+
| |
| Dr Nova 2003-11-08, 7:24 pm |
| > The network is 198.168.10.0/24. You wish to add a node to the network.
> What would be a valid address?
>
> a. 192.168.1.10
> b. 192.168.10.10
> c. 192.168.10.254
> d. 192.168.10.255
B & C
| |
| David K 2003-11-09, 12:24 am |
| On 8 Nov 2003 15:15:43 -0800, ibidibi411@hotmail.com (John) wrote:
>Hi Aaron-- congratlations on passing! Coincidentally, I passed this
>morning with a 793, too!
>
>On your 198.168.10.0/24 question, I remember that one, but I think you
>got one of the choices wrong. Choice B was "192.167.10.10". I know,
>because I was just about to pick B until I noticed the "7", which
>would put it outside the range of private addresses. I chose "C"
>instead. I really had to look closely to spot the difference.
I did the same thing. I kind of assumed they were all 168 until I was
left with apparently two correct answers.
Dave
| |
| Charles M. Kozierok 2003-11-09, 8:25 am |
| In article < 3ihrqvoqeg7bpd4nvqeop7sovibhco
b7b1@4ax.com>,
David K <noemail@fake.com> wrote:
} On 8 Nov 2003 15:15:43 -0800, ibidibi411@hotmail.com (John) wrote:
}
} >Hi Aaron-- congratlations on passing! Coincidentally, I passed this
} >morning with a 793, too!
} >
} >On your 198.168.10.0/24 question, I remember that one, but I think you
} >got one of the choices wrong. Choice B was "192.167.10.10". I know,
} >because I was just about to pick B until I noticed the "7", which
} >would put it outside the range of private addresses. I chose "C"
} >instead. I really had to look closely to spot the difference.
}
} I did the same thing. I kind of assumed they were all 168 until I was
} left with apparently two correct answers.
This is the sort of question that lead to so many people, including
myself, thinking these certifications are a near-meaningless joke.
Questions on a certification exam should attempt to determine the
subject's knowledge by providing incorrect answers that might be
selected due to a lack of understanding. Putting an answer on the test
that would be correct if not for a digit being off by 1 is appropriate
for an exam taken by someone studying to be a proofreader, not a
networking tech.
peace,
-*-
charles
| |
|
| David K <noemail@fake.com> wrote in message news:< 3ihrqvoqeg7bpd4nvqeop7sovibhco
b7b1@4ax.com>...
> I did the same thing. I kind of assumed they were all 168 until I was
> left with apparently two correct answers.
That's one thing I've noticed about the CompTIA tests: you can usually
whittle-down the answer just by eliminating the nonsensical stuff. We
both knew that there could not be two correct answers, so we looked
more closely at the choices. The trick is that you have to be totally
on your toes with some of them. My first action when answering a
question is to start eliminating the ones I know for sure are
incorrect and I double-check that I'm satisfied that they are not
right before I eliminate them. It doesn't always work, but it's a
pretty solid technique.
Ben
Network+ A+ TCP
| |
|
| See the notes InLine.
"Charles M. Kozierok" <ixlu@PCGuide.com> wrote in message
news:boipr3$85l$1@reader2.panix.com...
> Most of this is true but not all is technically correct.
> The "slash notation" is what is used in *classless* addressing, not
> classful. Also known as Classless Inter-Domain Routing (CIDR).
I agree in what CIDR means but that is all.
Slash notation (correctly named CIDR notation) is used for both classful and
classless network IDs.
CIDR itself is used for SuperNetting and allow Internet authorities and ISPs
to dole out network IDs with masks other then /8, /16 and /24 but CIDR
notation is a defacto standard used to describe masks of any kind.
/N : A written notation with the same meaning as "n-bit network mask." For
instance, the notation 172.18.250.3/24 means that the mask is 255.255.255.0.
> It is true that slash notation and subnet mask notation are often
> interchanged but CIDR is not the same as subnetting and is not based on
> network classes at all and does not use subnet masks in the way that
> classful subnetting used that concept.
For your own piece I suggest that you stop thinking of CIDR as the same as
"CIDR notation". I never said a word in my post about CIDR and I am not
going to write a book about it here. The original post was about SubNetting
and that was what I described.
And I have to admit (even if no one has complained yet) that /16 and /24
could be SubNets. 
AT
| |
| Charles M. Kozierok 2003-11-10, 7:24 am |
| In article <h_Frb.7458$6c3.1141@newsread1.news.pas.earthlink.net>,
AT <torgny@@direcway.com> wrote:
} Slash notation (correctly named CIDR notation) is used for both classful and
} classless network IDs.
Yes... but it was developed for classless routing, and you only
mentioned classful and not classless addressing.
} CIDR itself is used for SuperNetting and allow Internet authorities and ISPs
} to dole out network IDs with masks other then /8, /16 and /24 but CIDR
} notation is a defacto standard used to describe masks of any kind.
} /N : A written notation with the same meaning as "n-bit network mask." For
} instance, the notation 172.18.250.3/24 means that the mask is 255.255.255.0.
Which I said just below.... the notations are interchangeable, the only
problem with your previous post was strictly tying the concept to
"classful" addressing. It is a classless addressing concept now also
adopted to refer to classful networks and/or subnets.
} For your own piece I suggest that you stop thinking of CIDR as the same as
} "CIDR notation". I never said a word in my post about CIDR and I am not
} going to write a book about it here.
Well you should have said a word about it. Saying "/8 /16 /24 is not
Subnetting but Classfull Network IDs" is at best confusing, at worst
plain incorrect. What you probably wanted to say is that /8, /16 and /24
are means of expressing networks of the sizes corresponding to the old
Class A, B and C networks using CIDR or slash notation.
} And I have to admit (even if no one has complained yet) that /16 and /24
} could be SubNets.
Part of the problem is referring to /8, /16 and /24 networks using CIDR
notation without using non-integral-byte prefix lengths is that this
propagates the old classful concepts, which the Internet no longer uses.
In fact, this is probably the biggest problem with how IP addressing is
taught today: too much emphasis on classful addressing, strict
subnetting and /8, /16 and /24.
peace,
-*-
charles
| |
|
| After reading my old post and also yours, I have no problems at all to find
doubtful expressions in all of them.
As stated in my first reply I tried to make a short story about this not
writing a book and everything was about SubNetting.
For anyone that want the full story I can recommend "TCP/IP addressing"
written by Buck Graham.
There are a lot of books written about this and this is a good first one to
start with.
AT
"Charles M. Kozierok" <ixlu@PCGuide.com> wrote in message
news:bonuq8$l4a$1@reader2.panix.com...
> In article <h_Frb.7458$6c3.1141@newsread1.news.pas.earthlink.net>,
> AT <torgny@@direcway.com> wrote:
> } Slash notation (correctly named CIDR notation) is used for both classful
and
> } classless network IDs.
>
> Yes... but it was developed for classless routing, and you only
> mentioned classful and not classless addressing.
>
> } CIDR itself is used for SuperNetting and allow Internet authorities and
ISPs
> } to dole out network IDs with masks other then /8, /16 and /24 but CIDR
> } notation is a defacto standard used to describe masks of any kind.
> } /N : A written notation with the same meaning as "n-bit network mask."
For
> } instance, the notation 172.18.250.3/24 means that the mask is
255.255.255.0.
>
> Which I said just below.... the notations are interchangeable, the only
> problem with your previous post was strictly tying the concept to
> "classful" addressing. It is a classless addressing concept now also
> adopted to refer to classful networks and/or subnets.
>
> } For your own piece I suggest that you stop thinking of CIDR as the same
as
> } "CIDR notation". I never said a word in my post about CIDR and I am not
> } going to write a book about it here.
>
> Well you should have said a word about it. Saying "/8 /16 /24 is not
> Subnetting but Classfull Network IDs" is at best confusing, at worst
> plain incorrect. What you probably wanted to say is that /8, /16 and /24
> are means of expressing networks of the sizes corresponding to the old
> Class A, B and C networks using CIDR or slash notation.
>
> } And I have to admit (even if no one has complained yet) that /16 and /24
> } could be SubNets.
>
> Part of the problem is referring to /8, /16 and /24 networks using CIDR
> notation without using non-integral-byte prefix lengths is that this
> propagates the old classful concepts, which the Internet no longer uses.
>
> In fact, this is probably the biggest problem with how IP addressing is
> taught today: too much emphasis on classful addressing, strict
> subnetting and /8, /16 and /24.
>
> peace,
>
> -*-
> charles
| |
| Paisleyskye 2003-11-19, 6:25 pm |
| Congrats on the pass!
--
Paisleyskye
http://www.icertify.net
"Aaron Appelbaum" <aaronappelbaum.remove.@yahoo.com> wrote in message
news:qjcgqvc8fnclb66u86m2ifjgj
0r929ju8s@4ax.com...
> Hello all. I passed with a score of 793. I had a question I hope one
> of you can answer.
>
> The network is 198.168.10.0/24. You wish to add a node to the network.
> What would be a valid address?
>
> a. 192.168.1.10
> b. 192.168.10.10
> c. 192.168.10.254
> d. 192.168.10.255
>
>
> I picked B. I've never seen the foward slash with a number after a
> network address before. Does that refer to subnetting? What does it
> mean?
>
> Aaron Appelbuam
> A+, Network+
| |
| Øyvind Løken 2003-12-04, 7:24 pm |
| Aaron wrote:
The network is 198.168.10.0/24.
You wish to add a node to the network.
What would be a valid address?
a. 192.168.1.10
b. 192.168.10.10
c. 192.168.10.254
d. 192.168.10.255
The answer is B and C because:
A node is: Used to identify a såesific device in an internetwork.
Can be a hardware address, which is burned into the network interface card
or
a logical network address, which an Administrator or Server assign to the
node.
Out of the IP address: 192.168.10.0/24
This is what the Calc put out:
The Maskbit is: 24
Subnet bits: 0
Host Bits: 8
Max Subnet: 1
Max Hosts: 254
Current Network: 192.168.10.0
Current Host Range: 192.168.10.1 to 192.168.10.254
Subnet Mask: 255.255.255.0
Broadcast: 192.168.10.255 (Which is in answer D)
(To be absolutely sure I'v used a IP subnet Mask Calculator from Boson.)
So, Dr Nova must be right, it is answer B and C.
Cause 192.168.10.10 and 192.168.10.254 is both inside the valid host range:
192.168.10.1 - 192.168.10.254.
And answer A is another Network.
Oyvind Loken
"Dr Nova" <dr_nova@hospital.com> skrev i melding
news:bojtph$tt$1@usenet.otenet.gr...
>
>
> B & C
>
>
| |
| Oyvind L 2003-12-04, 7:24 pm |
| By the Aaron, Congratulation on the Pass. :-)))
Oyvind Loken
| |
|
| /? could be a subnet mask only
On Tue, 11 Nov 2003 07:59:27 GMT, "AT" <torgny@@direcway.com> wrote:
>After reading my old post and also yours, I have no problems at all to find
>doubtful expressions in all of them.
>As stated in my first reply I tried to make a short story about this not
>writing a book and everything was about SubNetting.
>For anyone that want the full story I can recommend "TCP/IP addressing"
>written by Buck Graham.
>There are a lot of books written about this and this is a good first one to
>start with.
>
>AT
>
>"Charles M. Kozierok" <ixlu@PCGuide.com> wrote in message
>news:bonuq8$l4a$1@reader2.panix.com...
>and
>ISPs
>For
>255.255.255.0.
>as
>
| |
|
| if it is still not used today what is used IP V6?
On Tue, 11 Nov 2003 07:59:27 GMT, "AT" <torgny@@direcway.com> wrote:
>After reading my old post and also yours, I have no problems at all to find
>doubtful expressions in all of them.
>As stated in my first reply I tried to make a short story about this not
>writing a book and everything was about SubNetting.
>For anyone that want the full story I can recommend "TCP/IP addressing"
>written by Buck Graham.
>There are a lot of books written about this and this is a good first one to
>start with.
>
>AT
>
>"Charles M. Kozierok" <ixlu@PCGuide.com> wrote in message
>news:bonuq8$l4a$1@reader2.panix.com...
>and
>ISPs
>For
>255.255.255.0.
>as
>
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