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Home > Archive > alt.certification.cisco > March 2004 > Failed exam, need explanation for following question:
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Failed exam, need explanation for following question:
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| I don't understand how to calculate binair to asci. (i know binair and
decimal ofcourse 
Your new junior trainee, Rutger, has a problem with basic binary math. He
must convert the
binary number 10011101 into its decimal and hexadecimal equivalent.
Which two numbers must Rutger provide? (Select two options)
A. 158
B. 0x9D
640 - 801
- 18 -
C. 156
D. 157
E. 0x19
F. 0x9F
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| On Tue, 30 Mar 2004 10:57:44 GMT, "Ron" <ron@mephesto.com> wrote:
> I don't understand how to calculate binair to asci. (i know binair and
>decimal ofcourse
>
>
>
>Your new junior trainee, Rutger, has a problem with basic binary math. He
>must convert the
>binary number 10011101 into its decimal and hexadecimal equivalent.
>Which two numbers must Rutger provide? (Select two options)
>A. 158
>B. 0x9D
>640 - 801
>- 18 -
>C. 156
>D. 157
>E. 0x19
>F. 0x9F
>
OK, ignore ASCII for the moment. What you're dealing with is binary to
hex conversion (and binary to decimal, but you've already said you're
OK with that).
The easiest way is to treat the 8-bit binary value as 4 high-order
bits and 4 low-order bits, so:
10011101 == 1001 1101
Each of these 4-bit "fields" can take values from 0 to 15 (dec), which
just so happens to coincide with the values that a single hex digit
can take (0x0 - 0xF).
So, you can say:
1001 == 9 (dec) == 0x9, and
1101 == 13 (dec) == 0xD, so
10011101 == 157 (dec) == 0x9D
It's actually easier than binary to decimal if you think about it in
those terms.
Hope this helps
Steve
( Strictly speaking, of course, what you're really doing is:
10011101 == 10010000 + 00001101, and
10010000 == 0x90,
00001101 == 0xD
So, 10011101 == 10010000 + 00001101 == 0x90 + 0xD == 0x9D)
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| X-Eliminator 2004-03-30, 11:26 am |
| What Cisco exam was this on?
I don't ever remember seeing a question like this on the 6 exams that
I have taken.
==============================
======================
On Tue, 30 Mar 2004 10:57:44 GMT, "Ron" <ron@mephesto.com> wrote:
> I don't understand how to calculate binair to asci. (i know binair and
>decimal ofcourse
>
>
>
>Your new junior trainee, Rutger, has a problem with basic binary math. He
>must convert the
>binary number 10011101 into its decimal and hexadecimal equivalent.
>Which two numbers must Rutger provide? (Select two options)
>A. 158
>B. 0x9D
>640 - 801
>- 18 -
>C. 156
>D. 157
>E. 0x19
>F. 0x9F
>
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| Peter Howkins 2004-03-30, 11:26 am |
| X-Eliminator wrote:
>
> What Cisco exam was this on?
>
> I don't ever remember seeing a question like this on the 6 exams that
> I have taken.
>
Shame, I'd hoped it or something similar would be on the CCNA, I can
actually do this question
Peter
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| I've seen it on the Cisco CCNA exam that I took 1 month ago. Thnx for your
replies all.
"X-Eliminator" <blablabla@aohell.com> wrote in message
news:305j609o3vt88odvkkf8qk81d
bvetha6c6@4ax.com...
> What Cisco exam was this on?
>
> I don't ever remember seeing a question like this on the 6 exams that
> I have taken.
>
> ==============================
======================
> On Tue, 30 Mar 2004 10:57:44 GMT, "Ron" <ron@mephesto.com> wrote:
>
>
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| X-Eliminator 2004-03-30, 11:25 pm |
| OK. I must be from the stone age. I have never seen a question on a
Cisco exam that had more than 4 or 5 answers.
==============================
===========================
On Tue, 30 Mar 2004 18:32:00 GMT, "Ron" <ron@mephesto.com> wrote:
>I've seen it on the Cisco CCNA exam that I took 1 month ago. Thnx for your
>replies all.
>
>
>"X-Eliminator" <blablabla@aohell.com> wrote in message
> news:305j609o3vt88odvkkf8qk81d
bvetha6c6@4ax.com...
>
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| Old Garb 2004-03-31, 2:25 am |
|
"X-Eliminator" <blablabla@aohell.com> wrote in message =
news:ccek60lns0i1n9t2kpob9v0p3
kt69bduq4@4ax.com...
> OK. I must be from the stone age. I have never seen a question on a
> Cisco exam that had more than 4 or 5 answers.
The 640-801 CCNA exam now requires binary, decimal and hex conversions.
=20
> =
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D
=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D
=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D
> On Tue, 30 Mar 2004 18:32:00 GMT, "Ron" <ron@mephesto.com> wrote:
>=20
your[color=blue]
that[color=blue]
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D
=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D
=3D=3D=3D=3D=3D=
=3D=3D[color=blue]
binair and[color=blue]
math. He[color=blue]
equivalent.[color=blue]
>
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| Ft4Bredn 2004-03-31, 7:25 pm |
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Hex is easy.. break the Binary into groups of four... so 1001 and 1101
convert them to hex ---> 1001 = 9 and 1101 = 13 or d in hex
so 10011101 = 9d or 0x9d
then convert the 10011101 to decimal or convert the 9d to decimal,
whichever is easiest for you.
9 X 16 + 13= 157 base 10
so b and d are the correct answers
On Wed, 31 Mar 2004 06:04:17 GMT, "Old Garb" <oss@attbi.com> wrote:
[color=blue]
>
>"X-Eliminator" <blablabla@aohell.com> wrote in message news:ccek60lns0i1n9t2kpob9v0p3
kt69bduq4@4ax.com...
>
>The 640-801 CCNA exam now requires binary, decimal and hex conversions.
>
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