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Home > Archive > alt.certification.cisco > March 2003 > IP subnetting
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| Baruah 2003-03-25, 3:24 am |
| Hello all,
Plz. help
Identify 3 valid host addresses in the
192.168.27.0 network with the mask 255.255.255.240
1. 192.168.27.33
2. 192.168.27.112
3. 192.168.27.119
4. 192.168.27.126
5. 192.168.27.175
I think non of the results are correct as I feel the address range for
the network(192.168.27.0) with the mask 255.255.255.240 is from
192.168.27.1 to 192.168.27.14
I would like to know the comments from every one from the group
| |
| cis_fun 2003-03-25, 5:24 am |
| Baruah wrote:
> Hello all,
>
> Plz. help
>
> Identify 3 valid host addresses in the
> 192.168.27.0 network with the mask 255.255.255.240
>
> 1. 192.168.27.33
> 2. 192.168.27.112
> 3. 192.168.27.119
> 4. 192.168.27.126
> 5. 192.168.27.175
>
> I think non of the results are correct as I feel the address range for
> the network(192.168.27.0) with the mask 255.255.255.240 is from
> 192.168.27.1 to 192.168.27.14
>
> I would like to know the comments from every one from the group
2. 192.168.27.112 - this is an adress of subnet
5. 192.168.27.175 - this is a broadcast adress
So the rest of address (1,3,4) are ok.
256-240=16
This are some subnets for 255.255.255.240 :
x.x.x.0
x.x.x.16
x.x.x.32
x.x.x.48
x.x.x.64
x.x.x.80
x.x.x.96
x.x.x.112
x.x.x.128
x.x.x.144
x.x.x.160
x.x.x.176
x.x.x.192 etc
.....
x.x.x.224
--
Rafal M
| |
| Mark Bedingfield 2003-03-25, 5:24 pm |
| Just checked rafel is bang on.
192.168.27.33 is ok
192.168.27.112 is ok is a network address for the .112 network
192.168.27.119 is ok
192.168.27.126 is ok
192.168.27.175 is a broadcast address for the .160 network
Just remember it is class B and you are borrowing 4 bits, so the ranges are
(according to Cisco), .16-.31, .32-.47, .48-.63, .64-.79, .80-.95, .96-.111,
..112-.127,.128-.143, .144-.159, .160-.175, .176-.191, .192-.207, .208-.223,
..224-.239.
Also remember the first and last subnets are unavaliable according to
cisco.So the .0 - .15 is the network address and the .240 - .255 is the
broadcast address of the subnetwork. Also as a note the rfc says you can use
these, but in the CCNA you CAN'T.
Mark
"Baruah" <b_baruah@hotmail.com> wrote in message
news:506277bd.0303250057.23756cb8@posting.google.com...
> Hello all,
>
> Plz. help
>
> Identify 3 valid host addresses in the
> 192.168.27.0 network with the mask 255.255.255.240
>
> 1. 192.168.27.33
> 2. 192.168.27.112
> 3. 192.168.27.119
> 4. 192.168.27.126
> 5. 192.168.27.175
>
> I think non of the results are correct as I feel the address range for
> the network(192.168.27.0) with the mask 255.255.255.240 is from
> 192.168.27.1 to 192.168.27.14
>
> I would like to know the comments from every one from the group
| |
| cis_fun 2003-03-25, 6:24 pm |
| Mark Bedingfield wrote:
> Just remember it is class B and you are borrowing 4 bits, so the ranges are
> (according to Cisco), .16-.31, .32-.47, .48-.63, .64-.79, .80-.95, .96-.111,
> .112-.127,.128-.143, .144-.159, .160-.175, .176-.191, .192-.207, .208-.223,
> .224-.239.
>
Well, I think that it is class C.  .
--
Rafal M
| |
| Mark Bedingfield 2003-03-25, 8:23 pm |
| Doh...It was before my morning coffee:-)
Mark
"cis_fun" <usun_boby2002@wp.pl> wrote in message
news:b5qpbb$m5b$1@korweta.task.gda.pl...
> Mark Bedingfield wrote:
>
> > Just remember it is class B and you are borrowing 4 bits, so the ranges
are
> > (according to Cisco), .16-.31, .32-.47, .48-.63, .64-.79, .80-.95,
..96-.111,
> > .112-.127,.128-.143, .144-.159, .160-.175, .176-.191, .192-.207,
..208-.223,
> > .224-.239.
> >
>
> Well, I think that it is class C. .
>
> --
> Rafal M
>
| |
|
| I think you are right and the question is wrong, they ask for the network
192.168.27.0/28
the network is 192.168.27.0, the broadcast is 192.168.27.15 so all usable
hosts are in between that range.
Danny
"Baruah" <b_baruah@hotmail.com> wrote in message
news:506277bd.0303250057.23756cb8@posting.google.com...
> Hello all,
>
> Plz. help
>
> Identify 3 valid host addresses in the
> 192.168.27.0 network with the mask 255.255.255.240
>
> 1. 192.168.27.33
> 2. 192.168.27.112
> 3. 192.168.27.119
> 4. 192.168.27.126
> 5. 192.168.27.175
>
> I think non of the results are correct as I feel the address range for
> the network(192.168.27.0) with the mask 255.255.255.240 is from
> 192.168.27.1 to 192.168.27.14
>
> I would like to know the comments from every one from the group
| |
| Mark Bedingfield 2003-03-27, 5:24 am |
| They mention the Network not the subnetwork. Cisco will try to use this to
make sure that you realise the Subnetwork is a seperate entity. So if they
said:
Identify 3 valid host addresses in the
192.168.27.0 Subnetwork with the mask 255.255.255.240.
Then you would be right. Because it is class c, the Network address is
192.168.27.0. The first Subnetwork is obviously 192.168.27.0 - .15, but is
unavaliable.
Mark
"Dan" <noddyholder@optusnet.com.au> wrote in message
news:3e82cb0e$0$16260$afc38c87
@news.optusnet.com.au...
> I think you are right and the question is wrong, they ask for the network
> 192.168.27.0/28
> the network is 192.168.27.0, the broadcast is 192.168.27.15 so all usable
> hosts are in between that range.
>
> Danny
>
> "Baruah" <b_baruah@hotmail.com> wrote in message
> news:506277bd.0303250057.23756cb8@posting.google.com...
> > Hello all,
> >
> > Plz. help
> >
> > Identify 3 valid host addresses in the
> > 192.168.27.0 network with the mask 255.255.255.240
> >
> > 1. 192.168.27.33
> > 2. 192.168.27.112
> > 3. 192.168.27.119
> > 4. 192.168.27.126
> > 5. 192.168.27.175
> >
> > I think non of the results are correct as I feel the address range for
> > the network(192.168.27.0) with the mask 255.255.255.240 is from
> > 192.168.27.1 to 192.168.27.14
> >
> > I would like to know the comments from every one from the group
>
>
| |
|
| "Dan" <noddyholder@optusnet.com.au> wrote:
>I think you are right and the question is wrong, they ask for the network
>192.168.27.0/28
>the network is 192.168.27.0, the broadcast is 192.168.27.15 so all usable
>hosts are in between that range.
But as with all good testers, we must come up with the correct answer,
despite the incorrect question.
So, there is no valid answer to your question, but if you are to pick
three, you would have to pick 1, 3, & 4, as explained by Mark.
Marc
>"Baruah" <b_baruah@hotmail.com> wrote in message
>news:506277bd.0303250057.23756cb8@posting.google.com...
>> Hello all,
>>
>> Plz. help
>>
>> Identify 3 valid host addresses in the
>> 192.168.27.0 network with the mask 255.255.255.240
>>
>> 1. 192.168.27.33
>> 2. 192.168.27.112
>> 3. 192.168.27.119
>> 4. 192.168.27.126
>> 5. 192.168.27.175
>>
>> I think non of the results are correct as I feel the address range for
>> the network(192.168.27.0) with the mask 255.255.255.240 is from
>> 192.168.27.1 to 192.168.27.14
>>
>> I would like to know the comments from every one from the group
>
For email, remove the first "y" of "whineryy"
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