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Home > Archive > alt.certification.cisco > June 2002 > Sub net question
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| Shawn Dorsey 2002-06-26, 10:25 pm |
| All,
This is taken from the Cisco Flash Card Practice kit and I
think it is wrong...
Given the IP address 172.156.100.100, mask 255.255.255.224, choose the
appropriate broadcast address.
172.156.100.127
172.156.100.255
172.156.100.31
172.156.100.128
I thought with a subnet mask of 224, 3 bits are borrowed for
subnetting resulting in an increment of 32. So the network address is
172.156.100.96...right? With an increment of 32 the next network
address is .128? So the broadcast is 172.156.100.127?
The practice kit says the answer is 172.156.100.128.
Anyone? Anyone?
| |
| Duane 2002-06-27, 12:25 am |
| On Thu, 27 Jun 2002 03:27:51 GMT, sdcd@mail.shreve.net (Shawn Dorsey)
wrote:
>All,
> This is taken from the Cisco Flash Card Practice kit and I
>think it is wrong...
>
>Given the IP address 172.156.100.100, mask 255.255.255.224, choose the
>appropriate broadcast address.
>
> 172.156.100.127
> 172.156.100.255
> 172.156.100.31
> 172.156.100.128
>
>I thought with a subnet mask of 224, 3 bits are borrowed for
>subnetting resulting in an increment of 32. So the network address is
>172.156.100.96...right? With an increment of 32 the next network
>address is .128? So the broadcast is 172.156.100.127?
>
>The practice kit says the answer is 172.156.100.128.
>
>Anyone? Anyone?
you are right, it should be 172.156.100.127
| |
| sllv521 2002-06-27, 1:25 am |
| << Given the IP address 172.156.100.100, mask 255.255.255.224, choose the
appropriate broadcast address.
172.156.100.127
172.156.100.255
172.156.100.31
172.156.100.128
I thought with a subnet mask of 224, 3 bits are borrowed for
subnetting resulting in an increment of 32. So the network address is
172.156.100.96...right? With an increment of 32 the next network
address is .128? So the broadcast is 172.156.100.127?
The practice kit says the answer is 172.156.100.128.
>>
ABSOLUTELY INCORRECT!!!!!!! It is 127, and a broadcast address is NEVER EVER
EVER EVER A EVEN ADDRESS.
Cisco need a thorough paddling for such a wrong answer
| |
| mo sule 2002-06-27, 2:25 pm |
| You are right the flash card is wrong...
So the broadcast is 172.156.100.127
"Shawn Dorsey" <sdcd@mail.shreve.net> wrote in message
news:3d1a7819.140972940@news.shreve.net...
> All,
> This is taken from the Cisco Flash Card Practice kit and I
> think it is wrong...
>
> Given the IP address 172.156.100.100, mask 255.255.255.224, choose the
> appropriate broadcast address.
>
> 172.156.100.127
> 172.156.100.255
> 172.156.100.31
> 172.156.100.128
>
> I thought with a subnet mask of 224, 3 bits are borrowed for
> subnetting resulting in an increment of 32. So the network address is
> 172.156.100.96...right? With an increment of 32 the next network
> address is .128? So the broadcast is 172.156.100.127?
>
> The practice kit says the answer is 172.156.100.128.
>
> Anyone? Anyone?
| |
| Steve Sechrist 2002-06-28, 12:25 pm |
| Sounds like you have the right answer.
Steve
"Shawn Dorsey" <sdcd@mail.shreve.net> wrote in message
news:3d1a7819.140972940@news.shreve.net...
> All,
> This is taken from the Cisco Flash Card Practice kit and I
> think it is wrong...
>
> Given the IP address 172.156.100.100, mask 255.255.255.224, choose the
> appropriate broadcast address.
>
> 172.156.100.127
> 172.156.100.255
> 172.156.100.31
> 172.156.100.128
>
> I thought with a subnet mask of 224, 3 bits are borrowed for
> subnetting resulting in an increment of 32. So the network address is
> 172.156.100.96...right? With an increment of 32 the next network
> address is .128? So the broadcast is 172.156.100.127?
>
> The practice kit says the answer is 172.156.100.128.
>
> Anyone? Anyone?
| |
| suntzzu 2002-06-28, 8:25 pm |
| you are correct!!!
"Steve Sechrist" <zkulicNOT@t-online.de> wrote in message news:<afi7r7$grg$04$1@news.t-online.com>...
> Sounds like you have the right answer.
>
> Steve
>
> "Shawn Dorsey" <sdcd@mail.shreve.net> wrote in message
> news:3d1a7819.140972940@news.shreve.net...
> > All,
> > This is taken from the Cisco Flash Card Practice kit and I
> > think it is wrong...
> >
> > Given the IP address 172.156.100.100, mask 255.255.255.224, choose the
> > appropriate broadcast address.
> >
> > 172.156.100.127
> > 172.156.100.255
> > 172.156.100.31
> > 172.156.100.128
> >
> > I thought with a subnet mask of 224, 3 bits are borrowed for
> > subnetting resulting in an increment of 32. So the network address is
> > 172.156.100.96...right? With an increment of 32 the next network
> > address is .128? So the broadcast is 172.156.100.127?
> >
> > The practice kit says the answer is 172.156.100.128.
> >
> > Anyone? Anyone?
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