| Author |
RAM in Cisco Equipment
|
|
| kwftide 2001-07-03, 10:17 am |
| Anyone have concrete information on how to determine the amount of RAM in a Cisco router or switch? When I do a sh ver, it is confusing to look at the shared/main memory section. Do I add them? It seems different between switches and routers.
Any ideas? | |
| strikeattack 2001-07-05, 9:43 am |
| If I remember correctly, SHOW MEMORY can show you available RAM, but the output was cryptic. I will see if I can come back with a better respnse when I get a moment from work. | |
| Retired-Mod 2001-07-06, 3:29 am |
| RAM you add together from sh ver. Flash ya don't have to add. | |
| netport 2001-07-06, 6:16 pm |
| IF you see this 16304/2303<-----this means that there is 16 meg ram w/2 meg soldered ram, so all together is 18 meg ram. That's quite normal due to some routers has on-board ram. | |
| Retired-Mod 2001-07-07, 5:31 pm |
| Maybe at one time there was soldered RAM, but I ain't ever seen it and I can tell you that the display in "show version" of xxxxK/xxxxK referring to RAM shows a logical split of your available RAM into to two special segments. I wish I could remember the meaning of each memory group but I can't. I can say with absolute certainity that it is a logical split and has nothing to do with physically seperate RAM.
Retired-Yankee | |
| netport 2001-07-08, 12:30 pm |
| Your correct its logical, The first set represent ram available, the second set represent ram used.
16340<----first set/2300<-----second set
combine the 2 and you have 18 megs. Have you ever seen an 18 meg ram? I've seen 16 megs. | |
| Retired-Mod 2001-07-08, 2:16 pm |
| No it is not RAM used and RAM available. Load a 8M IOS and you will not see an 8M split. Please research your answers before posting bad info.
Retired | |
| kwftide 2001-07-09, 8:14 am |
| Anyone know of a Cisco doc? | |
| netport 2001-07-09, 10:51 am |
| Ok, mis info. Its not used ram but its shared ram for interface buffers.
A quote from a ccie
"cisco 2500 (68030) processor (revision A) with 16384K/2048K bytes of
memory.
The figures 16384/2048 in the above line refer to MAIN DRAM/SHARED DRAM.
MAIN DRAM is used for storing routing tables and the like, and SHARED DRAM
is used mostly for the interface buffers. On 2500 revisions A through N the
SHARED DRAM is soldered to the board. So in this case you have a 16MB DRAM
simm and 2MB Shared DRAM which is on the board. The later revisions (after N
I think) logically carve SHARED memory from the MAIN DRAM (ie there is no
onboard SHARED DRAM).
16384K bytes of processor board System flash (Read ONLY)
This line refers to flash. You have 16MB flash. This flash device is
considered READ ONLY because you are running the IOS from FLASH.
Best regards
John" | |
| Retired-Mod 2001-07-10, 3:12 am |
| Thank you!
Now that's a good post 
Retired |
|
|
|