| Author |
Mon 70-217 Question of the Day
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| wbafrank 2002-06-24, 7:09 am |
| And today's poser is ....
Q4. Operations masters are domain controllers that have been assigned one or more special roles in an Active Directory domain. These roles are single-master which means that the operations they perform cannot be performed by other domain controllers at the same time. There are a total of five operations masters:
Domain Naming Master
Schema Master
PDC Emulator
RID Master
Infrastructure Master
The total number of operations masters that you will have is dependent on the number of domains in your Active Directory Infrastructure. Which of the following mathematical formulas correctly represents the number of operations masters that you will have?
A. 2*X + 2 where X is the number of domains in your Active Directory Infrastructure
B. 3*X + 2 where X is the number of domains in your Active Directory Infrastructure
C. 3*X - 2 where X is the number of domains in your Active Directory Infrastructure
D. 2*X + 3 where X is the number of domains in your Active Directory Infrastructure
E. 2*X - 2 where X is the number of domains in your Active Directory Infrastructure
F. 3*X + 3 where X is the number of domains in your Active Directory Infrastructure
Good Luck .... see you tomorrow for the answer!! | |
| Zaraspook 2002-06-24, 8:30 am |
| How about B?  | |
| Slinky 2002-06-24, 9:25 pm |
| Definately B. | |
| CyberDude 2002-06-25, 5:50 am |
| I have not seen this equation in my study materials. I have not got a clue.  | |
| Slinky 2002-06-25, 7:33 am |
| I have never seen the formula either, but knowing how many FSMO roles there are in a domain you can deduce it. As you already know there is only one Schema Master and one Domain Naming Master in a forest. And there is one RID Master, Infrastructure Master, and PDC Emulator in each domain. So if you have 3 domains, you will have 3 x the number of domains. The 3 is the constant because there are 3 roles per domain. So this would give you 9 for the domain level roles. The two is the other constant because there are only 2 roles per forest. For a grand total of 11 roles for the forest. Hope you understand. It's rather simple.  | |
| wbafrank 2002-06-25, 10:42 am |
| quote: Originally posted by wbafrank
And today's poser is ....
Q4. Operations masters are domain controllers that have been assigned one or more special roles in an Active Directory domain. These roles are single-master which means that the operations they perform cannot be performed by other domain controllers at the same time. There are a total of five operations masters:
Domain Naming Master
Schema Master
PDC Emulator
RID Master
Infrastructure Master
The total number of operations masters that you will have is dependent on the number of domains in your Active Directory Infrastructure. Which of the following mathematical formulas correctly represents the number of operations masters that you will have?
A. 2*X + 2 where X is the number of domains in your Active Directory Infrastructure
B. 3*X + 2 where X is the number of domains in your Active Directory Infrastructure
C. 3*X - 2 where X is the number of domains in your Active Directory Infrastructure
D. 2*X + 3 where X is the number of domains in your Active Directory Infrastructure
E. 2*X - 2 where X is the number of domains in your Active Directory Infrastructure
F. 3*X + 3 where X is the number of domains in your Active Directory Infrastructure
And the answer is ....
Correct Answer: B
The operations master roles of Domain Naming Master and Schema Master are forest-wide. This means that you will have only one machine with each role regardless of the number of domains that you have. The PDC Emulator, RID Master and Infrastructure Master roles are domain-wide. You will have one of each of these for every domain in your company. Therefore, the correct formula to determine the total number of operation masters would be 3*X + 2 where X is the number of domains in your Active Directory Infrastructure. For instance, if you had four domains the total number of operations masters would be 14 or 3*4 + 2. | |
| CyberDude 2002-06-25, 12:32 pm |
| Thanks for the explanation guys.  |
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