| Author |
Wed 70-216 Question of the Day
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| wbafrank 2002-04-03, 10:24 am |
|  And today's poser is ....
Q63. A company has designed a network, which has a DHCP server with a DHCP client placed on Subnet1. In Subnet2 they have placed two DHCP clients. A router separates Subnet1 and Subnet2 (with DHCP/BOOTP relay enabled). As this network is experiencing heavy traffic, they have asked you what measures could they use to reduce the traffic. What do you advice? (Choose all that apply)
A. You need to place a DHCP Relay agent on Subnet1 and disable DHCP/BOOTP forwarding on the router connecting Subnet1 and Subnet2.
B. You need to place a DHCP Relay agent on Subnet2 and disable DHCP/BOOTP forwarding on the router connecting Subnet1 and Subnet2.
C. Place a second DHCP server on Subnet1 and disable DHCP/BOOTP forwarding on the routers connecting Subnet1 and Subnet2.
D. Place a second DHCP server on Subnet2 and disable DHCP/BOOTP forwarding on the routers connecting Subnet1 and Subnet2.
E. None of the above.
Good Luck .... see you tomorrow for the answer!! | |
| KScheler 2002-04-03, 10:31 am |
| I'll go with B.& D.
With either of these choices you are enabling the dhcp clients on subnet2 to receive IP configurations and reduce network traffic, especially broadcast traffic. | |
| CyberDude 2002-04-03, 12:45 pm |
| If you do D then each subnet will have a server giving out addresses. The scopes will be different so there will be no cross-talk.
B will work as well, but as it is only a relay agent, you will still have cross-talking. | |
| jeff_j_black 2002-04-03, 1:10 pm |
| 'B & D' | |
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| if i understand dhcp correctly, doesn't a bootp-enabled router only allow bootp broadcast messages and discard 'general' broadcasts? if so, how much traffic could 2 clients actually cause when they only make bootp requests every 4 days (default lease time of 8 days) or once everytime the system reboots? seems to me that disabling the bootp function of the router or setting up another dhcp server or using a dhcp relay agent would not minimize traffic at all. in that case, i would have to go with answer "E". | |
| jeff_j_black 2002-04-03, 2:56 pm |
| em' I like your answer! | |
| Zaraspook 2002-04-03, 8:26 pm |
| How about B & D? 
Because all hosts must process broadcast traffic, disabling DHCP/BOOTP forwarding on the router connecting Subnet1 and Subnet2 would prevent broadcast traffic from traversing subnets and help to reduce network traffic.
Installing a DHCP relay agent ordinarily is not necessary because the router is rfc 1542 (DHCP/BOOTP) compatible, but because of high network traffic the network must be experiencing network bandwidth problems. In this case, installing a DHCP relay agent and disabling DHCP/BOOTP forwarding on the router connecting the two subnets would prevent broadcast traffic from traversing subnets and reduce network traffic. The DHCP relay agent would listen for the client's broadcast messages on subnet 2 and forward those messages as received to the DHCP server located on Subnet 1.
By placing a DHCP server on subnet 2, configuring a scope just for that subnet, and disabling DHCP/BOOTP forwarding on the router connecting Subnet1 and Subnet2, the clients on subnet 2 would use the local DHCP server and broadcast traffic would be prevented from traversing subnets reducing network traffic. | |
| unreal 2002-04-03, 8:29 pm |
| I think the best answer would be:
D. Place a second DHCP server on Subnet2 and disable DHCP/BOOTP forwarding on the routers connecting Subnet1 and Subnet2
And probably:
-Although I'm not sure why by doing it would reduce traffic ?
B. You need to place a DHCP Relay agent on Subnet2 and disable DHCP/BOOTP forwarding on the router connecting Subnet1 and Subnet2 would work | |
| mcdoud 2002-04-03, 11:00 pm |
| B & D
The relay agent talks directly to DHCP server, eliminating broadcasts from subnet 2 to subnet 1.
I also question the need with only 2 clients, but I do know that broadcasts need to be avoided if possible on a busy network. | |
| secondskin 2002-04-04, 12:16 am |
| B & D | |
| lamngocliem 2002-04-04, 5:39 am |
| My answer is E | |
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