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Spid's Fri (12/20) Win2k Pro. QoD
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| Ah yes, the weekend is here, and here's a question to tie you over until next week 
Soccer4net is the network administrator that has 140 hosts.
His supervisor advises him to divide the network into 10 subnets and each subnet must be able to accommodate up to 14 hosts. (We don't know why he needs 10 subnets for only 140 hosts, but his place is not to question why, just be a "yes man" and do it, he is told  )
How should soccer4net configure the IP addressing structure to allow for this configuration if the company's current IP addressing scheme is 194.194.194.0/24 ?
A. 194.194.194.0/25
B. 194.194.194.0/26
C. 194.194.194.0/27
D. 194.194.194.0/28
Good luck and see you Monday for the answer!! | |
| djmaplethorpe 2002-12-20, 10:12 am |
| quote:
Originally posted by Spid
How should soccer4net configure the IP addressing structure to allow for this configuration if the company's current IP addressing scheme is 194.194.194.0/24 ?
A. 194.194.194.0/25
B. 194.194.194.0/26
C. 194.194.194.0/27
D. 194.194.194.0/28
Good luck and see you Monday for the answer!!
If I did my calculations correct, on paper not with IPCalc, then I will go with "D" as you will get 16 subnets. Can't use the all 0's or all 1's, so that will leave you with 14 usable subnet. This should cover current needs and leave room for expansion.
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| soccer4net 2002-12-20, 3:01 pm |
| A question about me Yeah BABYYY!
And the answer is of course:
(D)
You get the 10 subnets (and then some) and 14 hosts per subnet. | |
| WPFossil 2002-12-20, 3:37 pm |
| I don't feel like doing the math on a Friday, so I'll take everyone's word for it and go with "D".
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| prajuab 2002-12-22, 8:56 pm |
| I choose D . | |
| namrak 2002-12-22, 10:54 pm |
| Going with answer (D) as well because you need to borrow 4 bits for the subnet mask to cover the amount of subnets and hosts needed. | |
| Victor Two 2002-12-23, 6:24 am |
| Yeah math on a Sunday night is pretty hard..
but I did it on paper and would say right answer is D.
16 subnets available with /28
8 subnets available with /27
4 subnets available with /26
2 subnets available with /25
Please correct if I'm wrong.. | |
| everetjo 2002-12-23, 10:09 am |
| i get D too... | |
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| quote:
Originally posted by Spid
Ah yes, the weekend is here, and here's a question to tie you over until next week
Soccer4net is the network administrator that has 140 hosts.
His supervisor advises him to divide the network into 10 subnets and each subnet must be able to accommodate up to 14 hosts. (We don't know why he needs 10 subnets for only 140 hosts, but his place is not to question why, just be a "yes man" and do it, he is told )
How should soccer4net configure the IP addressing structure to allow for this configuration if the company's current IP addressing scheme is 194.194.194.0/24 ?
A. 194.194.194.0/25
B. 194.194.194.0/26
C. 194.194.194.0/27
D. 194.194.194.0/28
Good luck and see you Monday for the answer!!
And the answer is.....D
Subnetting this out with a /28 mask will give us enough subnets to satisfy the 10 subnet requirement and enough hosts per subnet to satisfy the 14 host per subnet requirement.
The /25, /26 and /27 subnet masks do not meet the requirement of 10 subnets. (/28 does not give us exactly 10 subnets, but that's ok, we just have some extra to use if we need to later on).
Nice job everyone! | |
| brianh 2002-12-30, 2:26 am |
| Can anybody recommend a good book for subnetting. Thanks | |
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| quote:
Originally posted by brianh
Can anybody recommend a good book for subnetting. Thanks
Hi brianh,
Welcome to the forum.
Freak's subnetting guide is the one I would recommend.
http://www.mcsefreak.com/subnetting.htm
(Best of all, it's free )
Hope this helps. |
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