Windows 2000 track general

Author

win2000 tcp/ip

2000-12-19, 8:56 pm

I don't know why but i can't seemed to get my head round tcp/ip, I understand the basics behind it and even the binary structure but don't understand when i see questions that may state 194.194.194.0.28

what is the 28 all about, it may be obvious and i don't realise it.

Does it mean that my host start at 28 up to 255, or does it mean it goes up in blocks 28 then changes the 0 on the left to 1 when 28 hosts reaches 56 hosts.

I have been pulling my hair out, so could someone help me please.

Thanks
Zaca

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zaca

2000-12-19, 10:51 pm

194.194.194.0.28 is probably a typo meant to be 192.194.194.0/28. A /28 network means that the network portion of the ip address is 28 bits long. In otherwords it has a subnet mask of 255.255.255.240.

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Matt
CCDA, CCNA, Network+, A+

2000-12-20, 1:21 am

An octet is made of 8 bits. An IP address is made of 32 bits,there fore it has 4 octets.
When you look at a "regular" subnet mask, you see that we always take a full octet (255.0.0.0, class A), 2 full octets (255.255.0.0, Class B) or 3 full octects (255.255.255.0, class C)
You could say that a 255.255.255.0 subnet mask is 3 full octets, or 3*8=24 bits. You would use the /24 notation in this example, meaning that the first 24 bits in that subnet mask are represented by a 1 in binary, ie the first 24 bits in the IP Address are Network bits, and the rest are the host bits... makes sense?

I have a free subnetting guide online at www.mcsefreak.com/subnetting.htm

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2000-12-21, 5:47 pm

Excellent I understand now .

Thanks

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