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Author Broadcast
justindu

2003-09-16, 4:21 pm

Look at this example:

Visually, it is easy to see that to have 6 subnets, I will use 224 as a subnet bit and will start my first range at 32. I will then increment each range by that same value of 32. I love this chart!

My 6 ranges will be:



131.107.32.1 to 131.107.63.254

131.107.64.1 to 131.107.95.254

131.107.96.1 to 131.107.127.254

131.107.128.1 to 131.107.159.254

131.107.160.1 to 131.107.191.254

131.107.192.1 to 131.107.223.254


You cant assign the last IP to a host becuase it it used as the broadcast right?


So, 131.107.63.254 would be the broadcast and the last useable host would be 131.107.62.254 right?
Demijohn

2003-09-16, 4:40 pm

NO.

131.107.63.255 would be the broadcast address, and 131.107.63.254 is the last usable address in the 131.107.32.0 subnet.
martek

2003-09-16, 4:43 pm

For subnet 131.107.32.0 the broadcast address is 131.107.63.255 and the last valid address is 131.107.63.254.
Remember: the broadcast address is the last IP in the subnet, and the last valid IP is the broadcast address - 1. In this case 131.107.63.255 is the last IP in the 131.107.32.0 subnet cause if you add 1 to 131.107.63.255, you get 131.107.64.0, which is the next subnet ID.
I hope this helps.
justindu

2003-09-17, 12:03 am

Ok i think i got it...
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