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Home > Archive > CCNA > June 2003 > Subnetting 101 - LAB 06/13/2003
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Subnetting 101 - LAB 06/13/2003
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| anchor40 2003-06-13, 10:14 am |
| Good morning, on this fine Friday the 13th!!!!
Here's today's practice question:
Given the following IP address and mask, provide the class,
network ID, # subnets, and # of hosts per net:
code:
Address/mask Class Net ID #subs # hosts
================== ===== ================== ======= ========
___.___.___.___/__ _ ___.___.___.___/__ _______ ________
106.2.248.72 /28
4.162.23.229 /16
172.31.127.221 /29
216.221.221.216 /27
Your boss has asked you to audit the IP address allocation and report back with the maximum number of subnets available. For example, if 112.52.46.0 /27 were available, he wants to know the /28, /29, and /30 networks possible from that address.
In use (with IP Subnet-zero)are:
112.52.46.4 /30
112.52.46.8 /30
112.52.46.12 /30
112.52.46.32 /28
112.52.46.48 /28
112.52.46.80 /28
112.52.46.96 /27
112.52.46.128 /26
112.52.46.192 /26
112.52.47.0 /27
112.52.47.64 /26
112.52.47.128 /29
112.52.47.144 /29
112.52.47.160 /27
112.52.47.192 /26
Bonus: What's the summarized network address for all these subnets?
Answer:
code:
112.52.46.0 /30
112.52.46.16 /28
112.52.46.16 /29
112.52.46.24 /29
112.52.46.16 /30
112.52.46.20 /30
112.52.46.24 /30
112.52.46.28 /30
112.52.46.64 /28
112.52.46.64 /29
112.52.46.72 /29
112.52.46.64 /30
112.52.46.68 /30
112.52.46.72 /30
112.52.46.76 /30
112.52.47.32 /27
112.52.47.32 /28
112.52.47.48 /28
112.52.47.32 /29
112.52.47.40 /29
112.52.47.48 /29
112.52.47.56 /29
112.52.47.32 /30
112.52.47.36 /30
112.52.47.40 /30
112.52.47.44 /30
112.52.47.48 /30
112.52.47.52 /30
112.52.47.56 /30
112.52.47.60 /30
112.52.47.136 /29
112.52.47.136 /30
112.52.47.140 /30
112.52.47.152 /29
112.52.47.152 /30
112.52.47.156 /30
Bonus: The networks summarize into 112.52.46.0 /23
P.S. File away the attached sheet - it will help you in the "real world"  | |
| B4yaman3 2003-06-16, 8:22 am |
| Can you explain how did you get the /23 | |
| soccer4net 2003-06-17, 6:56 pm |
| To summarize, you need a subnet that will cover all the networks, without changing the network portion of the address. So if you look at the 3rd octet:
0010111|0 = .46.0
That last bit can be changed to a one(giving us 47) without changing the network portion. To get this we need /23. So we moved the subnet mask position one bit back from a /24:
0010111(0/1).|00000000 /24
changed to
0010111|(0/1).00000000 /24
Got subnetting? | |
| anchor40 2003-06-18, 2:43 pm |
| Thanks for the assist, Soccer4net!
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