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Subnetting 101-Lab 05/06/2003
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| anchor40 2003-05-06, 10:41 am |
| code:
Good Morning!! Here's today's practice question:
Which of the following statements are true?
A. 172.16.168.0/27 is a valid host address
B. 172.16.168.255/23 is a valid host address
C. 172.16.168.0/23 is not a valid host address
D. 172.16.168.255/26 is a valid host address
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Here are the answers to the 5/5/03 question:
Given the following IP address and mask, provide the class, network ID,
# subnets, and # of hosts per net:
Address/mask Class Net ID #subs # hosts
================== ===== ================== ======= ========
___.___.___.___/__ _ ___.___.___.___/__ _______ ________
201.17.24.27/28 C 201.17.24.16/28 14 14
Net 201. 17. 24. 27
Mask 255.255.255.240
201.017.024.0001 1001
255.255.255.1111 0000
-----------|SN |----- <--subnets
----------------| H | <--hosts
6.122.3.92/24 A 6.122.3.0/24 0 254
Net 6.122. 3. 92
Mask 255.255.255. 0
6.122. 3.0101 1100
255.255.255.0000 0000
---------- <-subnets
------| H | <--hosts
135.256.17.1/20 Illegal address (2nd octet of 256)
126.0.0.1/16 B 126.0.0.0/16 0 65534
Net 126. 0. 0. 1
Mask 255.255. 0. 0
126. 0. 0.0000 0001
255.255. 0.0000 0000
------------- <--subnets
--| H | <--hosts
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| PooPooPlatter 2003-05-06, 9:50 pm |
| I was checkin answer and found out there is an mistake. Last octet "27" in binary is "11011" instead of "11001"
Q1
Net 201. 17. 24. 27
Mask 255.255.255.240
201.017.024.0001 1001
255.255.255.1111 0000
-----------|SN |----- <--subnets
----------------| H | <--hosts | |
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| PooPooPlatter 2003-05-06, 10:30 pm |
|  I like to thank you for the practice questions. You put that much effort putting them together and I am taking CCNA on Friday, might as well do some more exercises. | |
| anchor40 2003-05-06, 10:33 pm |
| Thanks!!!
Be sure to check out tomorrow's question then.  | |
| PooPooPlatter 2003-05-06, 11:34 pm |
| Ok, the answer to this question is C. |
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