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| mcorpuz 2002-02-15, 10:35 am |
| You have a network address of 139.7.0.0 with the default subnet mask. You want to create 30 subnets using as few masked bits as possible. What subnet mask will you use? NOTE: Be sure to enter your answer as a 4 octet, dotted decimal.
I thought that the answer was 139.7.248.0. Where does my errot lie?
Also:You have a network address of 202.97.15.0 with the default subnet mask. You want to create 5 subnets using as few masked bits as possible. What subnet mask will you use? NOTE: Be sure to enter your answer as a 4 octet, dotted decimal.
For this I answered:202.97.15.224. | |
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| jlauri 2002-02-15, 11:02 am |
| you need this
11111111.11111111.11111111.11111000
255.255.255.248
/29
2^5 = 32 - 2 = 30
[]īs | |
| mcorpuz 2002-02-15, 11:05 am |
| Using the fewest borrowed bit from a Class B address, wouldn't it just be 255.255.248.0 | |
| jlauri 2002-02-15, 11:06 am |
| quote:
Originally posted by jlauri
you need this
11111111.11111111.11111111.11111000
255.255.255.248
/29
2^5 = 32 - 2 = 30
[]īs
sorry,
11111111.11111111.11111000.0000000
255.255.248.0
/21
2^5=32-2=30 | |
| mcorpuz 2002-02-15, 11:08 am |
| Thanks. What a stupid mistake I made. I forgot to put the subnet mask in the proper format. I just transferred the network address over and then the mask. Dah. Thanks for you help |
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Have a look on