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Author Please Help!!
nervous

2001-07-26, 11:22 am

hey everyone!
tired from all that studying!
Well, i had a question... please don't just read and go away? please help me with the subnetting question... i realize subnetting is not everyone's fav subject... but i hope you can help!

ok, here it is...
the address is 148.157.0.0
class b
need 500 networks and a max of 100 hosts.
i need to know the valid subnets, & valid hosts

thanks soooooo much! i have tried the question myself... but not at all confident .. so i would really appreciate your help on this question!

THANKS!
raydawg30

2001-07-26, 12:48 pm

OK, here's my outlook on the question. You need at least 500 subnets so your going to have to use 9 bits for your subnet, 2 raised to the 9th power minus 2 gives you 510 useable subnets. This gives you a subnet that would look like this 255.255.255.128, it looks almost like you should be doing a class C but because you need so many useable subnets your forced to borrow more bits than the 3rd octet has. Anyway, since you borrowed 9 bits for the subnet and you had a grand total of 16 bits to borrow from this leaves you with 16 - 9 = 7 bits to use for hosts, 2 raised to the 7th power minus 2 (for network and broadcast addys) should give you 126 available hosts per subnet. OK there it is in a nutshell, that is if I didn't goof on my math or something.

Good Luck

R.
dmaftei

2001-07-26, 12:53 pm

148.157.0.0 255.255.255.128 will give you 512 subnets, with 128 addresses per subnet (126 of which are usable for hosts). The subnets are:

148.157.0.0, 148.157.0.128,
148.157.1.0, 148.157.1.128,
148.157.2.0, 148.157.2.128,
...
148.157.254.0, 148.157.254.128,
148.157.255.0, 148.157.255.128
nervous

2001-07-26, 1:33 pm

thanks a lot guys! means a lot to me that you actually took the time to help me!

Good Luck with whatever you guys are going for!

and pray for me
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