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Home > Archive > CCNA > September 2000 > test on Friday
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| I am taking the test again this Friday. This will be my second attempt. I scored a 795 last Friday...does anyone know how many questions I was off from passing? I know that a passing score is 822, but I don't understand how that translates into the actual questions. Also...did most of you who took the test for the second time pass it? I have no prior router experience, and have studied solely Cisco's CCNA book, in addition to glancing at some braindumps.
I hope to report back successfully on Friday evening if I pass the test. Wish me luck. You guys have been very helpful.
Danny
CCNA hopeful | |
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| good luck for tomorrow!1
my turn should be next friday.
frans | |
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| I was told that the pass mark is 49/65, by one person and by another that it was 54/65. I think it's actually the former. My reasoning is as follows:
The Cisco scale is from 300 to 1000.
This equates to: 0% to 100% (Obviously)
If it's a linear function, then the formula for deriving the Cisco mark from a given percentage is: y = 300 + 7x
In your case, since you got 795, this means:
795 = 300 + 7x
7x = 495
x = 70.71 % or 45.96 (Let's assume 46).
So you were three marks off the pace (or thereabouts). Ouch!
Deets | |
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| Thanks for decoding the alegbraic mystery of Cisco. This helped to calm my nerves actually. I passed today with an 881. Yeah! | |
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| there's also the possibility that cisco weighs individual questions with different scores(ie, harder questions worth more points), which would totally throw the "average" out the window. It's a possibility.
However, if they score each question equally, and the score range is 300-1000, that means you start at 300. So in order to make a perfect score i'm assuming all 65 questions right = 1000. You must make up 700 points to get to 1000. So 700/65=10.76923076923 . This would be the average worth per question, roughly 11 points a question.
passing = 822, which means from 300 you need to make up 522 points. 522/10.76923076923 = 48.47142857142 . roughly 49 questions correct.
Again, this is all based on the assumption that each question is scored equally. So it really comes down to which scoring method they use. I kind of think there's different weights.
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| Good point, Detour. In fact, you'll note that I made a point that for my maths to be correct, the equation had to be linear.
Cheers,
Deets |
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