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QUESTION FOR CCNA ...NEED ANSWERS.
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| HI PEOPLE...
I GOT A COUPLE OF QUESTIONS...CCNA....
ANYONE CAN POST THEIR ANSWERS AND OPINION?
ANYONE VERIFY THE CORRECT ANSWERS BELOW...?
FROM HELAN.
HERE GOES:
1. If the access-group command is configured on an interface and there is no access-list created which of the following is most correct?
a) An error message will appear.
b) The command will be executed and deny all traffic out.
c) The command will be executed and permit all traffic out.
d) The command will be executed and permit all traffic in and out.
e) The command will be executed and deny all traffic in and out.
2. If Host A sends a packet to Host B over ethernet and Host B is not active:
a) The packet will time out.
b) The packet will be removed by Host A.
c) The NVRAM of Host B will remove the packet.
d) The packet will "die" when it reaches the terminator.
e) The packet will be removed by the token monitor.
3. Given the IP address of 193.243.12.43 and a subnet mask of 255.255.255.128, what is the subnet address?
a) 194.243.12.32
b) 193.243.0.0
c) 194.243.12.43
d) 193.243.12.128
e) None of the above.
4. The following statement would deny traffic from what subnets?
Router_B(config)#access-list 101 deny
tcp 10.1.8.0 0.0.7.255
192.16.5.0 0.0.0.255
a) 10.1.8.0
b) 10.1.15.0
c) 10.1.0.0
d) 10.1.16.0
e) choice a and b
5. Which of the following could be a feature of a connection-oriented service?
a) Flow Control
b) "Three-Way" hand shake
c) Error checking
d) Windowing
e) All of the above
6. The Media Access Control (MAC) address is made up of the following two parts.
a) Vendor Code
b) Network Address
c) Host Address
d) Serial Number
e) No such address
7. Which one of the following describes the process of a TCP/IP host learning a remote host MAC address?
a) ARP (Address Resolution Protocol)
b) SLARP (Serial Line Address Resolution Protocol)
c) RARP (Reverse Address Resolution Protocol)
d) IARP (Inverse Address Resolution Protocol)
e) MOP (Maintenance Operation Protocol)
8. What command Displays RIP routing updates send and received at router?
Sh ip rip 10.
Debug rip updates.
Debug ip rip.
Debug ip routing.
9. Which of the following options makes sure a routing packet never leaves the same interface it was learned from?
Poison reverse.
Split horizon.
Spanning tree.
Hold downs.
10. Which of the follow do not belong to the customer?
Router and DCE.
CO and CPE.
CO and Demarc.
DTE and CO.
DCE and CO.
11. What command would you use to turn on full RIP debugging for the IP protocol?
Debug RIP
Debug IP RIP
Debug RIP ON
Debug IP-RIP
12. A routers interface is described as 10.10.1.1/23. What is its subnet mask?
10.10.23.255
255.255.255.0
255.255.254.0
255.255.0.0
255.255.192.0
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| Helan,
I'll do my best....
1. If the access-group command is configured on an interface and there is no access-list created which of the following is most correct?
Not sure... never tried it. However, since the question doesn't specify whether the access-list is being applied inbound or outbound, I would assume that answers B, C, D, and E are probably wrong. My guess is A. Comments, anyone?
2. If Host A sends a packet to Host B over ethernet and Host B is not active:
d) The packet will "die" when it reaches the terminator.
Ethernet has no frame aging mechanism to keep frames from looping endlessly through the system. The packet will be absorbed when it reaches the terminator no matter what. Whether Host B gets it or not is immaterial.
3. Given the IP address of 193.243.12.43 and a subnet mask of 255.255.255.128, what is the subnet address?
e) None of the above.
The correct subnet address would be 193.243.12.0, and that option is not listed.
4. The following statement would deny traffic from what subnets?
Router_B(config)#access-list 101 deny
tcp 10.1.8.0 0.0.7.255
192.16.5.0 0.0.0.255
e) choice of a and b
Only the 11 right-most bits are 1's in source address wildcard mask. 10.1.8.0 and 10.1.15.0 are the only addresses given whose remaining left-most 21 bits (32-11) exactly meet the criteria for the access list command given.
5. Which of the following could be a feature of a connection-oriented service?
e) All of the above
These are all possible options for a connection-oriented service. Note that not all connection-oriented services implement all of these features.
6. The Media Access Control (MAC) address is made up of the following two parts.
a) Vendor Code
d) Serial Number
7. Which one of the following describes the process of a TCP/IP host learning a remote host MAC address?
a) ARP (Address Resolution Protocol)
8. What command Displays RIP routing updates send and received at router?
Debug ip rip.
9. Which of the following options makes sure a routing packet never leaves the same interface it was learned from?
Split horizon.
10. Which of the follow do not belong to the customer?
CO and CPE.
CO and Demarc.
DTE and CO.
DCE and CO.
The customer cannot own the CO (Central Office).
11. What command would you use to turn on full RIP debugging for the IP protocol?
Debug IP RIP
12. A routers interface is described as 10.10.1.1/23. What is its subnet mask?
255.255.254.0
The /23 means the entire mask is 23 bits starting with the leftmost bit. 24 bits would have been 255.255.255.0; one bit short of that would be 23, or 255.255.254.0.
Skip
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Whatever the mind of man can conceive and believe, it can achieve. | |
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| Helan:
I reviewed your questions and I am a bit concerned. I will take the CCNA exam next Friday.
Do you plan on taking the exam and if so, when?
What study resources have you used or do you plan on using?
I note the following question in particular:
7. Which one of the following describes the process of a TCP/IP host learning a remote host MAC address?
a) ARP (Address Resolution Protocol)
b) SLARP (Serial Line Address Resolution Protocol)
c) RARP (Reverse Address Resolution Protocol)
d) IARP (Inverse Address Resolution Protocol)
e) MOP (Maintenance Operation Protocol)
Helan, the fact that you ask this question almost tells me that you either do not have access to any resource materials or you need to make better use of your study resources.
What are your intentions and what resources do you use? If you need help in learning what study resources are worthwhile, I'll be glad to give you my thoughts and I assume other members of the group would too.
I am no expert by any means, but the above question is very elementary in regard to what one needs to know in order to pass, or even attempt to pass, the CCNA exam.
I'll help any way that I can. Let me know what your goal(s) are and when you want to achieve those goals. Then we'll move from there.
Please do not consider this an insult. There was a time when I could not answer the above question and your other questions. You CAN learn anything you make up your mind to learn and never forget that.
If you reply, I'll help you any way that I can provided you are willing to do your part.
Remember - there is NOTHING you cannot learn!
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| hi people...
i going to appear in the exam this friday...
hehhe...scared....
but have to finish it fast....
well people....thanks for posting the answers....really appreciate..
anyone can help me out ccna hard times
recommend me with any dumps or studyguide? | |
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| hi!!
My answers(i'm not insist)
1-b
2-a
9-poison reverse
Another answers is the same as above | |
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| thank u people......
for posting the answers and opinion....
well...
about question 1,2,9
anyone has the right confirmation or right
correct answers?
please feel free to post the opinion and answers to 1,2,9 and others...
i will post other questions soon.......
from helan | |
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| hi!!
My answers(i'm not insist)
1-b
2-a
9-poison reverse
Another answers is the same as above
1-d bcos i tested it practically. after applying an access-list in and out it allows me to telnet the router and from router i can ping the internet ip address. so it allows all the traffic in and out.
9-split horizon bcos poison reverse puts the down link to count to infinity
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| Only one of these questions bothers me - question no. 2.
Note to Skip: wouldn't the packet just die (ie. get killed). When they say packet here, do they mean frame? Terminator = AUI of interface card? (No, not Arnold Schwarzeneggar!) I have heard of IP packets simply dying...but with frames, I thought they would loop forever, unless STP was configured...
Sorry, a bit rambling at the moment...it's late.
Cheers,
Deets | |
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| you only have to eliminate all stupid answering-possibilities -
so the only answer, which will resist,
is answer a) because of hop-count-infinity.
and "packet" is the hint, that routing over ethernet is meant and not the switching-procedure...
when a packet is dropped because of running into hop-count-infinity it "dies".
a terminator (Schwarzenegger comes from my country austria) is something for preventing echos and reflections on a "physical" line, where only signaling and voltage-levels are influenced...
siegi
[This message has been edited by edlinger (edited 11-05-2000).]
[This message has been edited by edlinger (edited 11-05-2000).] | |
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| on question 4) the whole range from 10.1.8.0 up to 10.1.8.15 will be denied.
siegi
[This message has been edited by edlinger (edited 11-05-2000).] | |
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| on question 3) a subnetmask of 255.255.255.128 in classC-range is not allowed and even when it would be a legal mask, the address 193.243.12.43 would not be a part of that range.
siegi | |
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| quote:
Originally posted by Deets512:
Only one of these questions bothers me - question no. 2.
Note to Skip: wouldn't the packet just die (ie. get killed). When they say packet here, do they mean frame? Terminator = AUI of interface card? (No, not Arnold Schwarzeneggar!) I have heard of IP packets simply dying...but with frames, I thought they would loop forever, unless STP was configured...
Sorry, a bit rambling at the moment...it's late.
Cheers,
Deets
You can refer to frames as packets, but not vice-versa. People talk about Ethernet packets, but nobody talks about IP frames.
Here's what's happening in the scenario described by the question:
http://theskipster.tripod.com/ethernet.gif
Does anyone have any comments to describe this type of behavior in terms of the answer options given for question 2:
If Host A sends a packet to Host B over ethernet and Host B is not active:
a) The packet will time out.
b) The packet will be removed by Host A.
c) The NVRAM of Host B will remove the packet.
d) The packet will "die" when it reaches the terminator.
e) The packet will be removed by the token monitor.
Skip
[This message has been edited by TheSkipster (edited 11-05-2000).] | |
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| Hi.
The answer to question :
1 = d, because there is no list and secondly i have tried it on a live router.
3 = e, None of the above, because one bit subnetting is not possible and not due to the reason mentioned by theskipter. | |
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| I agree with you, waheed.
what's your opinion to the really nice network-plan of skip? 
concerning to question 2 -
what's your favourite?
a) or d) ?
siegi | |
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| Hi all,
I'm pretty sure the answer to question one is C.
I think this was covered in a course I took,
Reason:
the access list will contain the implicit
DENY ALL - event though no list exists.
I believe I remember my instructor warning us of this,
I assume it would also be outbound as that is the default and the question has not specified?
Comments? | |
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| the answer to 1 is d. This is the same question I got in the Exam cram CCIE book and the answer is that all traffice will be permited in and out as if there was not access list, because there really isn't any access list. | |
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| quote:
Originally posted by Jamesbond_007:
the answer to 1 is d. This is the same question I got in the Exam cram CCIE book and the answer is that all traffice will be permited in and out as if there was not access list, because there really isn't any access list.
Thanks Jamesbood007 !!!
I just tested this on r1r2.com, you are 100% right 
[This message has been edited by yango (edited 11-05-2000).]
[This message has been edited by yango (edited 11-05-2000).] | |
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| Hi Skip,
In the question, we can NOT learn that the network is connected with a coxial cable.
If there is a hub, the packet will never reach the terminator.
So, I think the packet will finally timeout.
What's your opinion?
Jason | |
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| Cool animation, Skip. How did you do that?
Deets | |
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| I just tried applying a non-existent access list to an interface, and the router accepted it. So I guess that means you can create your access list after applying it. Just thought I'd make a note of this.
Cheers,
Deets | |
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| Hello Helen,
so i m trying my best to answer your questions with the justifications i have, still i have not tried some questions on practical basis but as per my knowledge or guessing i answered them.
1) d-i think answer is (d) cause it it always better to create the access list before you apply it, so when u give the command and dont create any access list it will follow "implicit deny all" cause atleast one condition must be mentioned inoreder to allow the traffic to pass across router. but just by creating access group you cant implement access list.
2)a-i m not that much sure but the message will be"timed out"as the pc is not available to recieve the packet.
3)answer e-none of the above.
43= 0 0 1 0 1 0 1 1
128= 1 0 0 0 0 0 0 0
so answer is 192.243.12.0
4) e-both (A)n (B) r true.
7= 0 0 0 0 0 1 1 1
8= 0 0 0 0 1 0 0 0
9= 0 0 0 0 1 0 0 1
10= 0 0 0 0 1 0 1 0
11= 0 0 0 0 1 0 1 1
. . . . . . . . . .
. . . . . . . . . .
15= 0 0 0 0 1 1 1 1
___________________
16= 0 0 0 1 0 0 0 0
so it shows that the wildcars mask here is for 10.1.8.0 to 10.1.15.0 as till the third octate is 16= 0 0 0 0 1 0 0 0 all first 4 bits are 0s, so all nos between 8-15 will only be checked.
5)e-all of the above
6)Vendor code(internic spoecified) n Serial no.
7)ARP(address resolution protocol is used for resolving the MAC address for a given IP.
8)debug ip rip
9)Split Horizon
10)CO (Central Office and DCE)
11)debug ip rip
12)10.10.1.1/23 means first 2 octates all 1s i.e 255.255 n the last one is 1 1 1 1 1 1 1 0 i.e 254 so the correct answer is
255.255.254.0
I tried my best to answer all the questions but still i m not sure about questions
will try to check all questions that i m not much sure as soon as possible.
till then best of luck to all who are preparing for CCNA 2.0.
i cleared my CCNA 2.0 on 11th oct,2000.
NEEL | |
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| In earlier releases of IOS, if you applied a non-existent access-list to an interface, the router interpreted this as an access list having only the implicit deny any any rule and would therefore block all traffic.
Because this drove engineers insane (imagine making a typo and blocking all access to a remote site), they changed is behavior back in the 10.x days. Now a non-existent access list is interpreted as having a permit any any rule and will allow all traffic. After you place your first entry in the router it gathers the implicit deny any any rule and you typically knock yourself off the router. Not that i've ever done that or anything.
The moral of the story is never to apply an access list to interface unless you're completely done editing it.
MadChef | |
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| Jasonip,
What layer would the time-out feature be part of? Ethernet has no such feature that I know of... Certainly not a layer 2 function.
Deets,
A magician never tells his secrets...
A neat little program called GIF Movie Gear (www.gamani.com) and lots of free time!
I had seen some really neat animated smileys (like this: http://www.techmindworks.com/cgi-bin/users/forum/wink.gif ) on another forum I visit and I thought I would explore the exciting realm of GIF animation!
Of course, I had just had to show off at the very first opportunity, and there you have my nifty diagram of host A trying hopelessly to communicate with a very unconscious host B.
Skip
[This message has been edited by TheSkipster (edited 11-06-2000).] | |
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| In reference to Q#1 regarding access-list, i think the answer is*c*.As i am reading ACRC book fdited by Laura Chappel, it says
"If u apply an access-listwith the access-group command to an interface before any access-list lines have been created, the result will be permitted any,(page44) | |
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| answer to qestion
1- The command will be executed and permit all traffic in and out.
i am dame sure i did it on my routers.
second case is if u apply an access list to an interface with 1 permit statement it will have an implicit deny. so take care of this case.
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| quote:
Originally posted by CONREI2:
4. The following statement would deny traffic from what subnets?
Router_B(config)#access-list 101 deny
tcp 10.1.8.0 0.0.7.255
192.16.5.0 0.0.0.255
a) 10.1.8.0
b) 10.1.15.0
c) 10.1.0.0
d) 10.1.16.0
e) choice a and b
The answer for this ---> A
Someone said it should E (choice of a and b).
They are wrong  This is simply because B is not a valid subnet !!! Actually 10.1.15.0 is included in the subnet '10.1.8.0'.
Hope this help
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| 9. Which of the following options makes sure a routing packet never leaves the same interface it was learned from?
Poison reverse.
Split horizon.
Spanning tree.
Hold downs.
Answer: Poison reverse
Pls focus on "never leaves" which means included originated interface, right?
Split horizon blocks information about routes from being advertised by a router out any interface from which that information originated.
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| Hugh,
I hate to say this but you are wrong. You have things mixed up! Slit Horizon is used to no routing table update is sent out the interface is got the update from. PG 267 ICND, "The rule of split horizon is that it is never useful to send information about a route back in the direction from which the original udate came from."
Route Posoning is sending a recently downed link as having a infinited cost (hope count). See page 268 ICND | |
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| I search in the cisco WEB and i found this about the question 9
My answer is Split Horizon
The split horizon rule states:
Never advertise a route out of the interface through which you learned it.
Poison reverse is another way of avoiding routing loops. Its rule states:
Once you learn of a route through an interface, advertise it as unreachable back through that same interface
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| yeh, keya ho raha hai!
refering to the several post here daily sometime I go in more confusion . I will make humble request to the ciscoGURU who have just started thier study not to give thier opinion about the answers (as smug,johny181...did here ...) rather they should participate in the discussion and explore thier preperation refering the books and material on those particular topics ex. page no of xyz books say this and so on.
I agree mostly with Neel for the answers how ever i would like be specific about the final ans.
1) d-i think answer is (d) cause it it always better to create the access list before you apply it, so when u give the command and dont create any access list it will follow "implicit deny all" cause atleast one condition must be mentioned inoreder to allow the traffic to pass across router. but just by creating access group you cant implement access list.
madchef has clearifed this very effeciently , however I want him to look this also as shave contradict his post for the question below
1)On a frame relay interface serial 0, what subinterface numbers would you use.
a) 1 and 2
b) 0.2 and 0.3
c) some stupid choice
d) some stupid choice
"The answer is A, and I'll tell you why I think so....It is in 2 diff. study guides that way, and one practice test I had.....but in EXAM CRAM 640-507 book...In chapt. 16 page 311...there is an alert statement and I quote " The proper syntax for creating and accessing a subinterface is the interface number followed by a period (.) followed by the subinterface number. For example, serial 0.11 indicates the subinterface 11 on serial interface 0." Its not a decimal number the period just shows that it s a subinterface....represented by a whole number. It is a very poorly worded question to trick you. "
where as madchef said this You can use any number you like for the subinterface (well any number between 1 and something like 4 billion and change). Many people just use .1, .2, .3, etc. But a really cool way to document stuff is to make the subinterface number the same as the DLCI number. You could do something like this:
interface Serial0/1.402 point-to-point
description Connection to
ip address 192.168.254.9 255.255.255.252
frame-relay interface-dlci 402 .
so finally what is obivious correct ans for this
2)a-i m not that much sure but the message will be"timed out"as the pc is not available to recieve the packet.
skip d) The packet will "die" when it reaches the terminator. Ethernet has no frame aging mechanism to keep frames from looping endlessly through the system. The packet will be absorbed when it reaches the terminator no matter what. Whether Host B gets it or not is immaterial.
jason Hi Skip,
In the question, we can NOT learn that the network is connected with a coxial cable.
If there is a hub, the packet will never reach the terminator.
So, I think the packet will finally timeout.
What's your opinion?
I agree with jason and want to ask to skip that you said d) The packet will "die" when it reaches the terminator. so if the terminator is not exit viz.UTP or Fiber then what ?
3)answer e-none of the above.
43= 0 0 1 0 1 0 1 1
128= 1 0 0 0 0 0 0 0
so answer is 192.243.12.0
4) e-both (A)n (B) r true.
7= 0 0 0 0 0 1 1 1
8= 0 0 0 0 1 0 0 0
9= 0 0 0 0 1 0 0 1
10= 0 0 0 0 1 0 1 0
11= 0 0 0 0 1 0 1 1
. . . . . . . . . .
. . . . . . . . . .
15= 0 0 0 0 1 1 1 1
___________________
16= 0 0 0 1 0 0 0 0
so it shows that the wildcars mask here is for 10.1.8.0 to 10.1.15.0 as till the third octate is 16= 0 0 0 0 1 0 0 0 all first 4 bits are 0s, so all nos between 8-15 will only be checked.
yango -The answer for this ---> A Someone said it should E (choice of a and b).They are wrong This is simply because B is not a valid subnet !!! Actually 10.1.15.0 is included in the subnet '10.1.8.0'.
skip Only the 11 right-most bits are 1's in source address wildcard mask. 10.1.8.0 and 10.1.15.0 are the only addresses given whose remaining left-most 21 bits (32-11) exactly meet the criteria for the access list command given.
I would say yango to read ths question once again .
5)e-all of the above
6)Vendor code(internic spoecified) n Serial no.
7)ARP(address resolution protocol is used for resolving the MAC address for a given IP.
8)debug ip rip
9)Split Horizon
100%
10)CO (Central Office and DCE)
here techmind says CO and Demarc anybody ?
11)debug ip rip
12)10.10.1.1/23 means first 2 octates all 1s i.e 255.255 n the last one is 1 1 1 1 1 1 1 0 i.e 254 so the correct answer is 255.255.254.0
I would appreciate on replies for above comments.
I will be posting more questions very soon just to clear off my doubts
Anwar
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