|
Home > Archive > i-NET+ > May 2000 > Dowloading a file
You are viewing an archived Text-only version of the thread.
To view this thread in it's original format and/or if you want to reply to
this thread please [click here]
|
|
|
| Could someone please explain how to calculate downloading a file. For instance, you have a 1000 byte file over a 56K connection. How long does it take to download. Thanks | |
|
| To calculate download times:
1. Remember 1KB = 1024 bytes
2. Convert file size to KB by dividing. Ex: 1000 bytes = .9765625 bytes
3. Divide by connection speed Ex: .9765625/56Kbs=.017439 (rounded off). This will give you the portion of that file that will be downloaed in one second.
4. Convert to minutes Ex: .01749 times 60 equals 1.0476 minutes.
Hope this helps.
------------------
Rob Elder | |
|
| Hello all,
Rob, I don't mean to step on your toes here, but, you are way off base with that answer. Here's how to figure it:
56K is equal to 56,000 bits per second (not bytes as you stated).
Divide this by 8 (8 bits equal 1 byte)
56,000 divided by 8 = 7000 (roughly figuring)
So now we know we can download 7000 bytes per second with a 56K connection (provided everything is perfect, which never happens)
So, the answer to the question is .142857142 seconds to download a 1000 byte file. (a 1000 byte file is less than 1K)
Now, correct me if I am wrong, but, I truly believe this is correct. There's no need to figure how many minutes.
------------------
Adam Wright
A+, Network+, i-Net+ | |
|
| Not sure I want to bring this post up again but I think I need to.
Neither of the above responses seems correct to me.
I'm studying to take the exam currently and have not found an explanation of this computation in the dummies book. I know it is probably only one question on the test but regardless I would like to know this formula and can't seem to get a clear understanding of this issue.
Is one of these correct? Can someone that is absolutely clear on this respond? Thanks in advance! | |
|
| uk-fan is probably correct, and if not, he's at least close. There are 2 different definitions used for the kilo prefix: 1,000 and 1024.
Matt
CCNA, Network+, A+
[This message has been edited by itcert (edited 05-15-2000).] | |
|
| A friend of mine helped me with this. Here is an example, I hope it helps.
You have a 100K file and you are downloading at 128Kbps.
128 Kbps / 8 = 16
100 / 16 = 6.25 seconds
So with yours, its a 1 K file (or 1000 bytes)..so...
56 Kbps / 8 = 7
100 / 7 = 14.28 seconds to download.
Hope it helps. | |
|
| ----------------------------------------
Ok here we go you have a file that is 100k
you have a 128 kb/s ISDN.
instead of 8 bit for a byte we will use 10 bits as mid rate to allow for delays.
So 100KB x 10 = 1000 kb
1000 kb / 128 kb/s = 7.8 s or 8 s
NEXT
you have a 56kbs line and a 1K file
instead of 1024 we will use 1K
So 1000 x 10 = 10kb
10kb / 56kb/s = 1/6 s or .2 s
ok! OK!!
------------------
evazz
IBM CNE, A+ N+
|
|
|
|
|