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Question on practise test
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| The question below is in this site's practise test for NT workstation. According to them the right answer is D.
I think the right answer is B. Can somebody please tell me wich answer is correct?
(Does the fact of having FAT impede the stripe set? )
Practise Test question goes:
1.You are planning to reconfigure an NT Workstation with 32 MB RAM for optimum speed of access to its local (mainly graphic data) files, varying in size from 1 MB to 10 MB, for other computers in the same LAN. You have there a SCSI controller with 4 disks of 2 GB each, formatted with FAT. Required result : To optimize performance for optimum speed of access to local data files. Optional results : Reconfigure for optimum speed of access to paging file. Optimize network access performance. Proposed solution: Configure the first hard disk as boot partition. Configure the other 3 disks as a Stripe Set. Use FAT on all partitions. Place data and paging file on the Stripe Set. . Configure binding order of protocols; move the least used protocols to the top of binding order. The solution produces :
A. The required result and both of the optional results
B. The required result and one of the optional results
C. The required result and none of the optional results
D. None of the required results
Thank you for any help on this. | |
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| i believe formatting to NTFS is the faster of the two so that it why it doesnt meet the required results
[This message has been edited by kfash (edited April 30, 2000).] | |
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| Hi Jose,
I think you are absolutely correct and that "B" should be the correct answer. This is my first time posting on this discussion group and exactly the reason I was going to post.
Regardless of FAT (which in fact is faster than NTFS for the most part because of less overhead and security checks), a stripe set would achieve faster access as all 3 hard drives could read data at the same time. Not to mention that this would certainly increase the paging speeds.
Based on this, I have to agree with you.
Hope this helps, but I wish whoever takes care of "what is the correct answer" sees this post.
Al | |
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| quote:
Originally posted by Jose:
The question below is in this site's practise test for NT workstation. According to them the right answer is D.
I think the right answer is B. Can somebody please tell me wich answer is correct?
(Does the fact of having FAT impede the stripe set? )
Practise Test question goes:
1.You are planning to reconfigure an NT Workstation with 32 MB RAM for optimum speed of access to its local (mainly graphic data) files, varying in size from 1 MB to 10 MB, for other computers in the same LAN. You have there a SCSI controller with 4 disks of 2 GB each, formatted with FAT. Required result : To optimize performance for optimum speed of access to local data files. Optional results : Reconfigure for optimum speed of access to paging file. Optimize network access performance. Proposed solution: Configure the first hard disk as boot partition. Configure the other 3 disks as a Stripe Set. Use FAT on all partitions. Place data and paging file on the Stripe Set. . Configure binding order of protocols; move the least used protocols to the top of binding order. The solution produces :
A. The required result and both of the optional results
B. The required result and one of the optional results
C. The required result and none of the optional results
D. None of the required results
Thank you for any help on this.
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| Jose-
I am studying now for the Workstation test. I believe that the reason for the answer is in the last part of the solution: Put the LEAST used protocols to the top of the binding order. The most frequently used protocols should be at the top of the binding order to optimize performance. | |
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| I agree with 'B' too:
Required result: OK. With a stripe set I/O Requests are optimized. Also, in reality FAT ist faster than NTFS.
First optional result: OK. Placing the paging file to a physical disk other than the disk which contains the boot-/systempartition will decrease the activity on the paging file.
Second optional result: NOT OK. You should configure the binding protocols in that order, that the MOST used protocol is on the top (not the least used)
--> B. The required result and on of the optional results | |
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| I think the answer is D, because the partition size in FAT can't be greater
then 4GB | |
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| The reason the answer is D is this --
Yes a stripe set would speed up access to data BUT if you put a paging file over a stripe set it slows access down. For optimal performance the paging file should be placed on a partition that does not contain the system fles and that is not a part of a stripe or volume set. Plus by binding the protocols in the LEAST used order, you would also slow down the system. | |
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| Jose, I believe only NTFS partitions can be striped. Therefore if you use FAT, the scenario will not work.
quote:
Originally posted by Jose:
The question below is in this site's practise test for NT workstation. According to them the right answer is D.
I think the right answer is B. Can somebody please tell me wich answer is correct?
(Does the fact of having FAT impede the stripe set? )
Practise Test question goes:
1.You are planning to reconfigure an NT Workstation with 32 MB RAM for optimum speed of access to its local (mainly graphic data) files, varying in size from 1 MB to 10 MB, for other computers in the same LAN. You have there a SCSI controller with 4 disks of 2 GB each, formatted with FAT. Required result : To optimize performance for optimum speed of access to local data files. Optional results : Reconfigure for optimum speed of access to paging file. Optimize network access performance. Proposed solution: Configure the first hard disk as boot partition. Configure the other 3 disks as a Stripe Set. Use FAT on all partitions. Place data and paging file on the Stripe Set. . Configure binding order of protocols; move the least used protocols to the top of binding order. The solution produces :
A. The required result and both of the optional results
B. The required result and one of the optional results
C. The required result and none of the optional results
D. None of the required results
Thank you for any help on this.
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| You can stripe set both NTFS and FAT.
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| OK,Jose,I think I have the answer to your question.The frist time I read the question I agreed with the test anwser but I was not sure why I did so I did a little reading.
The reason why D is correct is because FAT is'nt used in partitions above 400meg
the stripe set used 3 partitions at 2 gig each,Hence the required result is not met. If I'm wrong,It's very late,so please don't talk about me. | |
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| Don't overlook the fact that the drives aren't formatted with NTFS.
The required result is to "optimize" local hard disk access. Striping is one aspect of optimization, but FAT vs NTFS is certainly another. If the drives are formatted with FAT instead of NTFS, then access to those drives can't be considered fully "optimized", even if striping is used, and the required result is not met.
Only if the drives were less than 200MB would NTFS NOT be considered "optimimum".
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| I hate this question too,but I think the Key is that under dos 6.22 2.1 gig is the limit. Under wks4 implementation of dos you have long file names(not relevant) and a partition size of 4 gig. The stripe set would exceed this by 2 gig making NTFS the only option.If the stripe set used 2 2 gig drives then it would work. | |
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| I also thouht 'B' was correct, but DanK got the key point. The stripe set is the problem.
The partion size is Too big for FAT. This is why the NTFS version of the question is worded the same, with a diffrenent answer than this one.
**As for FAT & Maximum drive sizes, if you want FAT for compatibility with DOS (etc..)then the Max size is 2G (using standard 32k clusters). If only NT is using the FAT partion you can use 64k cluster sizes and increase the max disk size to 4G. As a practical limit, 2G. As a test Question, 4G as it concerns FAT sizing & sole use by NT.**
As for the 400mb & FAT issues raised above. It is said that FAT poorly utilizes space on larger drives. But it can (and is) used on larger drives anyway for a variety of good reasons (DOS & OS2 compatibility being big ones). NTFS is optimized for drives greater than 400Mb, thus this can be seen as a reason to use NTFS rather than FAT on drives greater than 400Mb. There is no rule like "If the drive is greater than 400Mb, Use NTFS" for these compatibility (and the related disaster recovery) reasons.
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Know why the other
answers are wrong | |
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| Stripe set and Page Files do not like each other. Period. 
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Freak, MA, M.Ed., Net+,I-Net+, MCP+I, MCSE, MCT
http://www.mcsefreak.com | |
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| Jose consider this:
The question below is in this site's practice test for NT workstation. According to them the right answer is D.
I think the right answer is B. Can somebody please tell me which answer is correct?
(Does the fact of having FAT impede the stripe set? )
Practice Test question goes:
1.You are planning to reconfigure an NT Workstation with 32 MB RAM for optimum speed of access to its local (mainly graphic data) files, varying in size from 1 MB to 10 MB, for other computers in the same LAN. You have there a SCSI controller with 4 disks of 2 GB each, formatted with FAT.
Required result : To optimize performance for optimum speed of access to local data files.
Optional results :
Reconfigured for optimum speed of access to paging file.
Optimize network access performance.
Proposed solution:
Configure the first hard disk as boot partition.
Configure the other 3 disks as a Stripe Set.
Use FAT on all partitions.
Place data and paging file on the Stripe Set.
Configure binding order of protocols; move the least used protocols to the top of binding order.
The solution produces :
A. The required result and both of the optional results
B. The required result and one of the optional results
C. The required result and none of the optional results
D. None of the required results
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Ok having re-jigged the question now lets look at the components:
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If you have 3 SCSI controllers then 2 disks must be on the same controller.
C = Controller D = Disk
C1 has D1 & D2
C2 has D3
C3 has D4
Thus:
C1D1 has thew boot & system files (FAT16)
C1D2 & C2D1 & C3D1 Strip Set (assume without parity as it does not mention parity in the question) Formatted with FAT16(this gives faster read performance for disks under 400MB) You have 2GB disks(HINT). Thus it is NOT CORRECT
Placing the PageFile.sys on the stripe set does improve performance as it is using all 3 controllers on separate disks to access the file. Thus it is CORRECT
The Binding order in the proposed solution does optimise the network protocols thus this is CORRECT
Ok now look at the REQUIRED RESULT:
"To optimize performance for optimum speed of access to local data files." this cannot be true since for disks above 400MB MS recommends NTFS.
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The over all answer in my opinion is D  sorry to throw a meteor in you pool guys 
Comments please
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Yeti-GBR1
MCNE MCPx3 SCO ACE LCD Compaq ASE (Wannabe CCIE)
email: Yeti@zerg.com
http://www.mcse2000.plus.com
Yes I'm a Blizzard Brood War Veteran. |
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